Biology Reference
In-Depth Information
Example 3.6.
Consider a 3-node system having the following states in
Z
5
:
200
431
314
043
which we interpret as
s
1
=
2
0
→
t
1
=
4
1
,
,
0
,
,
3
,
s
2
=
4
1
→
t
2
=
3
4
,
,
3
,
,
1
,
s
3
=
3
4
→
t
3
=
0
3
.
,
1
,
,
4
,
The corresponding ideals are
I
(
s
1
)
=
x
1
−
2
,
x
2
,
x
3
,
I
(
s
2
)
=
x
1
−
4
,
x
2
−
3
,
x
3
−
1
,
.
To compute the intersection
I
of the ideals, we can use the computer algebra system
Macaulay 2 [
26
] with the following code:
I
(
s
3
)
=
x
1
−
3
,
x
2
−
1
,
x
3
−
4
R=ZZ/5[x1,x2,x3]
I1=ideal(x1-2,x2,x3)
I2=ideal(x1-4,x2-3,x3-1)
I3=ideal(x1-3,x2-1,x3-4)
I=intersect{I1,I2,I3}
.
Then
I
is computed as
2
x
3
+
x
3
+
−
x
1
+
2
x
2
+
x
3
+
2
,
2
x
2
x
3
−
x
3
,
−
x
2
x
3
−
x
2
+
x
3
,
x
2
+
2
x
2
−
x
2
x
3
+
2
x
2
+
2
x
3
,
2
x
2
x
3
+
x
2
,
x
1
x
2
+
x
1
x
3
+
x
2
+
x
3
,
2
−
2
x
1
x
2
+
2
x
1
x
3
−
x
1
−
x
2
+
x
3
+
.
Note that negative coefficients can be written as positive numbers:
−
1
≡
4mod5
,
−
2
3 mod 5, etc.
To find the function
f
1
(
≡
x
1
,
x
2
,
x
3
)
for node
x
1
such that
f
1
2
0
=
,
0
,
4
,
f
1
4
1
=
,
3
,
3
,
(3.1)
f
1
3
4
=
,
1
,
0
,
we compute the
r
polynomials:
r
1
x
1
,
x
3
=
2
4
3
x
1
−
4
2
3
3
x
1
−
3
=
3
x
1
+
x
2
,
−
−
4
x
1
+
1
,
r
2
x
1
,
x
3
=
4
2
3
x
1
−
2
4
3
3
x
1
−
3
=
3
x
1
+
x
2
,
−
−
3
,
r
3
x
1
,
x
3
=
3
2
3
x
1
−
2
3
4
3
x
1
−
4
=
4
x
1
+
x
2
,
−
−
x
1
+
2
.
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