Chemistry Reference
In-Depth Information
23. [pH = 8; pOH = 6]—Because we are given the concentration of OH
-
ions,
it is easier to find the pOH first.
pOH = -log[OH
-
] = -log(0.000001) = 6
pH = 14 - pOH = 14 - 6 = 8
24. [pH = 3; pOH = 11]—We are given the concentration of H
3
O
+
ions this
time, so it is easier to find the pH first.
pH = -log[H
3
O
+
] = -log(0.001) = 3
pOH = 14 - pH = 14 - 3 = 11
25. [pH = 4.1; pOH = 9.9]—Work shown following:
pH = -log[H
3
O
+
] = -log(0.000073) = 4.1. pOH = 14 - 4.1 = 9.9
