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2H 2 O + CO 2
methane + oxygen water + carbon dioxide
x dm 3
CH 4 + 2O 2
40 dm 3
methane
oxygen
coefficients
1
x
2
40 dm 3
=
# of moles
Cross-multiplying, we get 2x = 40 dm 3 , so the volume of methane is
20 dm 3 .
Before you move on to the practice problems, let me remind you one
more time that this shortcut may only be used for the volume-volume prob-
lems. The reason for this should be clear. All gases have a molar volume of
22.4 dm 3 /mole at STP; however, substances don't all have the same mass at
any temperature or pressure.
Now, on to the practice problems.
Lesson 7-6 Review
Answer questions 1-3 based on the following balanced chemical equa-
tion. Assume all volumes are at STP.
C 3 H 8 + 5O 2
4H 2 O + 3CO 2
propane + oxygen water + carbon dioxide
1.
How many dm 3 of oxygen are required to completely react with 5.0
dm 3 of propane?
2.
How many dm 3 of carbon dioxide will be produced if 15 dm 3 of
oxygen react with an excess of propane?
3.
How many dm 3 of water vapor will be produced with 90.0 dm 3 of
carbon dioxide?
Complete all of the required steps to answer the following questions.
Assume STP for all volumes of gases.
4.
How many dm 3 of hydrogen will react with 4.0 dm 3 of nitrogen in the
synthesis reaction that produces ammonia?
5.
How many dm 3 of oxygen are required to react with an excess of
glucose in order to produce 5.0 dm 3 of carbon dioxide through the
process of respiration?
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