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the corresponding SFrCI constraint is a capacity constraint (in this case, 3 .S j
/ D
1 .S/). So, the two terms in the left-hand side of ( 15.31 ) are identical, the two terms
in the right-hand side are also equal, and the inequality becomes:
X
S
rS r 1 .S/;
r2
which is the basic expression of the capacity constraint.
As is the case for other sets of inequalities, the framed capacity inequalities
(FrCI) where originally developed for two-index flow formulations and later
adapted to the set-partitioning formulation by using Eq. ( 15.29 ), and reinforced by
modifying the coefficients of the r variables as explained in the last section. The
FrCI for formulation LRP2 corresponding to .S;
S
/ is
0
@ X
1
t
X
X
z jk C 2 X
i2I
X
X
X
z jk C 2 X
i2I
A
z ij C
z ij
j2S
j2S
sD1
j2S s
k2V nS
k2V nS s
2 3 .S j
1 .S s / ! :
t
X
S
/ C
(15.32)
sD1
To illustrate that FrCI (and, therefore, SFrCI) is a broader set of inequalities that
can be stronger than the combination of capacity constraints for the individual sets
S s ,Fig. 15.3 gives an example of a fractional solution with
Df S 1 ; ;S 4 g ,
where the capacity constraints for each of the S s sets are satisfied, but the overall
FrCI constraint is violated. In this figure, customers are numbered from 1 to 7 and
w i is given inside each customer. Note that, in this example, we have S D[ sD1 S s ,
w .S/ D 20 and Q D 7,sothat 1 .S/ D 3. Thus, the capacity constraint for set S is
satisfied, since the total flow in edges with one endpoint in S equals its lower bound,
2 3 D 6. Also, for each set in the partition, w .S s /<Q,sothat 1 .S s / D 1 and the
S
Fig. 15.3 Example of
unsatisfied FrCI
 
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