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With the above preparations, the rank distribution of Π δ,γ ( x )canbedetermined
as follows. Since S (0 , 0 , 0) = p n , by Proposition 10 and the values of S ( γ,δ, 0)
corresponding to the rank of Π γ,δ ( x ), one has
p 2 (
)+ p 2 + d (
)+ p n =
|
R 0 , 1 |−|
R 0 ,− 1 |
|
R 2 d, 1 |−|
R 2 d,− 1 |
S ( γ,δ, 0) ,
γ∈ F p m
δ∈ F p n
1) p 2 p n + d
p n
+ p n +2 d
+ p 2 n =
S ( γ,δ, 0) 2 ,
|
R 0 |
+(
|
R d |
|
R 2 d |
γ∈ F p m
δ∈ F p n
p 3 2 (
)+ p 3 2 +3 d (
)+ p 3 n =
S ( γ,δ, 0) 3 .
|
R 0 , 1 |−|
R 0 ,− 1 |
|
R 2 d, 1 |−|
R 2 d,− 1 |
γ∈ F p m
δ∈ F p n
|
R 0 , 1 |
|
R 0 ,− 1 |
|
R d |
|
R 2 d, 1 |
|
R 2 d,− 1 |
This together with the equalities
+
+
+
+
=
p n + m
|
R i |
|
R i, 1 |
|
R i,− 1 |
( i =0 , 2 d )aswellasProposition9give
1,
=
+
p d ( p m +1)( p n
= ( p n + d
2 p n + p d )( p m
1)
1)
|
R 0 , 1 |
=
,
|
R 0 ,− 1 |
,
2( p d +1)
2( p d
1)
(14)
( p m d
1)( p n
1)
|
R 2 d, 1 |
=0 ,
|
R 2 d,− 1 |
=
.
p 2 d
1
Therefore, we have the following result.
Proposition 11. When ( γ,δ ) runs through
F p m
× F p n
\{
(0 , 0)
}
, the rank dis-
tribution of the quadratic form Π γ,δ ( x ) is given as follows:
( p m + n +2 d + p n + p m + d
p m + n
p m + n + d
p 2 d ) / ( p 2 d
n,
1) times ,
p m−d ( p n
n
d,
1) times ,
2 d, ( p m−d
1)( p n
1) / ( p 2 d
n
1) times .
4 Weight Distribution of the Nonbinary Kasami Codes
This section determines the weight distribution of the nonbinary Kasami codes
C
k . Further, we also give the distribution of S ( γ,δ, ), which will be used to derive
the correlation distribution of the sequence families proposed in next section.
Since the weight of the codeword c ( γ,δ, )isequalto p n
1
( N γ,δ, (0)
1) =
p n
N γ,δ, (0), it is sucient to find N γ,δ, (0) for any given γ,δ, .
Under the basis
i =1 i α i with i F p .
n
{
α 1 2 ,
···
n }
of
F p n over
F p ,let =
Then, Tr 1 ( x )= Λ T CX where Λ T =( 1 , 2 ,
p and the matrix C =
···
, n )
F
( Tr 1 ( α i α j )) 1 ≤i,j≤n , which is nonsingular since
{
α 1 2 ,
···
n }
is a basis of
F p n
F p .Thenlet X = BY as in Section 2 and Λ T CB =( b 1 ,b 2 ,
over
···
,b n ), one has
i =1 a i y i +
i =1 b i y i .
n
n
Π γ,δ ( x )+ Tr 1 ( x )= Y T B T ABY + Λ T CBY =
We calculate N γ,δ, ( ρ )( ρ
F p )and S ( γ,δ, ) as follows:
Case 1. ( γ,δ )=(0 , 0): the weight of c ( γ,δ, )is( p
1) p n− 1 for
=0,and0
=0,and p n for =0.
for =0.Then S (0 , 0 , )=0for
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