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Moreover, we have nl r ( F )
max
r ≤n (min ( λ r r )) ,where:
n
i
,
n
r
AI ( F )
r
1
1
r
λ r =2 m max
if r
AI ( F )
r
1 ,
i
i =0
i =0
n
i
if r >AI ( F )
AI ( F )
r
1
=2 m
r
1 ,
i =0
n
+2 m− 1
n
.
AI ( F ) −r
AI ( F ) −r− 1
r +1
i
r
μ r =2 m− 1
i
i =0
i =0
Proof. Let h be any n -variable function of degree at most r and let be any
m -variable nonzero linear function. We have d H (
F, h )= z∈supp ( ) |
F 1 ( z )
+ z∈supp ( +1) |
F 1 ( z )
supp ( h +1)
|
supp ( h )
|
.
F )= z∈supp ( ) |
F 1 ( z )
If h is constant, then d H (
F, h )equals w H (
|
or
F +1) = z∈supp ( +1) |
F 1 ( z )
w H (
which, according to the property recalled
before Proposition 2, are lower bounded by 2 m− 1 AI ( F ) 1
|
i =0 i .Itisasimple
matter to check that the bound of Theorem 1 is then satisfied.
If h is not constant, then Proposition 2 (last line of) implies d H (
F, h )
i =0 n− i .
The inequality
2 m AI ( F ) −r− 1
2 m− 1
n
i
+
n
AI ( F ) −r− 1
AI ( F ) −r− 1
r
nl r ( F )
i
i =0
i = AI ( F ) 2 r
is a direct consequence of Proposition 2 and of the inequality
dim Mul AI ( F ) −r− 1 ( h ) + dim Mul AI ( F ) −r− 1 ( h +1)
n
i
+
n
AI ( F ) −r− 1
AI ( F ) −r− 1
r
i
i =0
i = AI ( F )
2 r
which is a direct consequence of Lemma 2 and Corollary 6 in [46].
Let r be any nonnegative integer. If AI ( h )
r , then Proposition 2 shows
F 2 ,
F 1 ( z )
F 1 ( z )
that, for every z
|
supp ( h )
|
and
|
supp ( h +1)
|
are lower
bounded by
n
i
,
n − r
i
r
AI ( F ) −r− 1
1
if r
max
AI ( F )
r
1 ,
i =0
i =0
n
i
if r >AI ( F )
AI ( F ) −r− 1
r
1 .
i =0
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