Information Technology Reference
In-Depth Information
When (
m, n
)=(0
,
1), we have
⎧
⎨
s
(
t
−
jd
))
+
s
(
t
+(
i
+1)
d
+1)
s
(
t
+
τ
1
+(
j
+1)
d
+1)
,
if
τ
0
=0;
id
))(
−
s
(
t
+
τ
1
−
C
(
i,
0)
,
(
j,
1)
(
τ
)=
⎩
s
(
t
−
id
)
s
(
t
+
τ
1
+(
j
+1)
d
+1)
+
s
(
t
+(
i
+1)
d
+1)(
−
s
(
t
+
τ
1
+1
−
jd
))
,
if
τ
0
=1
=
−
C
s
(
τ
1
+
ad
)+
C
s
(
τ
1
−
ad
)
,
if
τ
0
=0;
C
s
(
τ
1
+
bd
+1)
−
C
s
(
τ
1
−
bd
)
,
if
τ
0
=1
.
When (
m, n
)=(1
,
0), we have
⎧
⎨
(
−
s
(
t
jd
)
+
s
(
t
+(
i
+1)
d
+1)
s
(
t
+
τ
1
+(
j
+1)
d
+1)
,
if
τ
0
=0;
−
id
))
s
(
t
+
τ
1
−
C
(
i,
1)
,
(
j,
0)
(
τ
)=
(
−
s
(
t
id
))
s
(
t
+
τ
1
+(
j
+1)
d
+1)
+
s
(
t
+(
i
+1)
d
+1)
s
(
t
+
τ
1
+1
−
⎩
−
jd
)
,
if
τ
0
=1
=
−
C
s
(
τ
1
+
ad
)+
C
s
(
τ
1
−
ad
)
,
if
τ
0
=0;
−
C
s
(
τ
1
+
bd
+1)+
C
s
(
τ
1
−
bd
)
,
if
τ
0
=1
.
T−
1
2
Case ii)
d
|
: Similar to the Proof of Case i).
Remark
: In Case i) of Lemma 1, it is easily checked that
ad
=
−
ad
mod
T
if
T−
1
2
0
≤
i, j
≤
f
−
1and(
i, j
)
=(0
,
0). The condition
d
implies
bd
+1
=
−
bd
mod
T
for any 0
≤
i, j
≤
f
−
1. Hence,
{
s
(
i,m
)
(
t
)
}
and
{
s
(
j,n
)
(
t
)
}
are cyclically
distinct if (
i, m
)
=(
j, n
). Cyclic distinctness for Case ii) can also be checked
similarly. Therefore, the set
IS
in (2) contains 2
f
cyclically distinct sequences
of period 2
T
.
T
−
1
Theorem 2.
Let
1
≤ d ≤
.Theset
IS
in (2) is a
(2
T,
2
f,
2
d,
2
)
M
-ary
2
LCZ sequence set, where
⎧
⎨
2
T−
1
4
d
for
d
T
−
1
2
f
=
2
T−
3
4
d
for
d
⎩
T
−
1
|
.
2
T−
1
2
Proof.
Consider the case that
d
. Without loss of generality, we can assume
that
i
≤
j
for
C
(
i,m
)
,
(
j,n
)
(
τ
). By Lemma 1, we have
|
C
(
i,m
)
,
(
j,n
)
(
τ
)
|≤
2
except for
(
τ
0
,τ
1
)=(0
,ad
)
,
(0
,T
−
ad
)
,
(1
,bd
)
,
(1
,T
−
bd
−
1)
which are equivalent to
τ
=2
ad,
2
T
−
2
ad,
2
bd
+1
,
2
T
−
2
bd
−
1
,