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By Lemma 1 the linear complexity of any 2 n -periodic sequence S with 2 n− 1 <
L ( S ) < 2 n
and merr ( S )=2 m +1 , m
∈{
1 ,
···
,n
2
}
, can be uniquely
expressed as
m +1
L ( S )=2 n
2 n−r i ,
(3)
i =1
where 1 <r 1 <
n . From equation (3), the linear complexity of any
2 n -periodic binary sequence S with 2 n− 1
···
<r m +1
<L ( S ) < 2 n and merr ( S )
2 m +1 ,
m
∈{
1 ,
···
,n
2
}
, can be bounded as
m− 1
m
2 n
2 n−r i +2 n−r m +1 ) <L ( S ) < 2 n
2 n−r i ,
(
(4)
i =1
i =1
for some r i ∈{
<r m .Wenotethat
the lower bound in inequality (4) can never be less than 2 n− 1 conforming to the
original condition 2 n− 1 <L ( S ) < 2 n . Also, for any sequence S satisfying the
inequality (4), we have merr ( S )
2 ,
···
,n
}
, i =1
···
m , satisfying 1 <r 1 <
···
2 m +1 . We also note that the bounds in (4)
are unique in the sense that the linear complexity of any 2 n -periodic sequence
S with merr ( S )
2 m +1
satisfies exactly one inequality of the particular form
given in equation (4).
For a 2 n -periodic sequence S and two integers i and j with 0
2 n
1,
denote by S i,j the 2 n -periodic binary sequence with corresponding polynomial
S i,j ( x )= S ( x )+ x i + x j . We use the following result by Fu et al. [3] for the main
result of this section.
i, j
( L ) ,where 2 n
2 n−r <L< 2 n
2 n−r− 1 for
Lemma 5. For any sequence S ∈A
2 n
some 1
r
n
2 , and for any integer 0
i
1 , the number of sequences
2 n
= i ,isexactly 2 r
S i,j ∈A
( L ) ,where 0
j
1 and j
1 corresponding
t 2 n−r
2 r
to all j
∈{
i
:1
t
1
}
where
is the operation of addition
modulo 2 n .
The rest of this section deals with extending Lemma 5 to the case when four
symbols per period are changed. For a 2 n -periodic binary sequence S and four
integers i, j, k ,and l with 0 ≤ i, j, k, l ≤ 2 n
1, denote by S i,j,k,l the 2 n -periodic
binary sequence with the corresponding polynomial
S i,j,k,l ( x )= S ( x )+ x i + x j + x k + x l .
The Games-Chan algorithm [4] is a fast algorithm to compute the linear com-
plexity of a 2 n -periodic binary sequence, which we use for the rest of this section.
For any S ∈A
( L ) with period S (2 n )
=( s 0 ,
···
,s 2 n 1 ), denote the left and
right halves of S (2 n ) by
S (2 n 1 )
L
,s 2 n 1 1 )and S (2 n 1 )
=( s 0 ,
···
=( s 2 n 1 ,
···
,s 2 n 1 ) .
R
Let S L and S R denote the 2 n− 1 periodic sequences
,s 2 n 1 1 ) and S R =( s 2 n 1 ,
,s 2 n 1 ) .
S L =( s 0 ,
···
···
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