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The question of when a ring R = Z [ π ] is a UFD is a delicate one, not fully
understood. First, it is generally necessary to use the integral closure of R rather
than R . The quadratic fields Z [ p ] whose integral closures are UFDs are known
for negative p , but they are not yet all known for positive p . The negative p for
which the integral closure of Z [ p ]isaUFDare
.
The known positive p for which the integral closure of Z [ p ]isaUFDare
{
{−
163 ,
67 ,
43 ,
19 ,
11 ,
7 ,
3 ,
2 ,
1
}
2,3,5,6,7,11,13,14,17,19,21,22,23,29,33,37,41,53,57,61,69,73,77,89,93,97
}
.
3Exp ed
π
-Adic Complexity
The function λ is extended to states of an AFSR D by λ ( a 0 ,
,a r− 1 ; m )=
r + λ ( m ). We extend λ to AFSRs by letting λ ( D, σ )denotethemaximumof
λ ( τ )overallstates τ that occur in the infinite execution of the AFSR starting
with initial state σ .Weextend λ to sequences by letting λ ( a ), the π -adic span
of a , be the minimum of λ ( D, σ )overall( D, σ )with D ( σ )= a . Also, let Γ n
denote the set of pairs ( D, σ ) such that D is an AFSR, σ is a state of D ,and
D ( σ )hasperiod n .
Now suppose that a is a sequence over S . Suppose that
···
α =
r
a i π i = u
q
q i π i
and
q =
q 0 ,
i =0
i =1
where q i
S for i =0 ,
···
,r , D q ( σ )= a for some initial state σ ,and λ ( a )=
λ ( D q ).
Lemma 3.
If a is strictly periodic, then λ ( a )
λ ( q )+ O (log( λ ( q ))) = r +
O (log( r )) .
Thus the size of the carry m has little effect on the π -adic complexity.
Let Γ n denote the set of pairs ( D, σ )
Γ n for which λ ( D, σ ) is minimal among
all pairs ( C, τ )with C ( τ )= D ( σ ). Suppose ( D, σ )
Γ n and q D = i =1 q i π i
q 0 .
Then
r
q i π i )+ c 3
λ ( D ( σ ))
r
λ (
i =1
by S4. Furthermore,
r
r
λ ( q D )= λ (
q i π i
q i π i ) ( q 0 )) + c 1
q 0 )
max( λ (
i =1
i =1
r
q i π i )+max( λ ( s ): s
λ (
S )+ c 1 .
i =1
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