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α 2 i
C α :=
{
: i
∈{
0 ,...,m
1
}}
.Wecanview
F
=
F 2 m as a vector space of
dimension m over
1)-dimensional linear subspace
of this vector space, and can be defined as one of the subsets H α :=
F 2 .A hyperplane is an ( m
{
x
F
:
Tr ( αx )=0
}
F
, for all nonzero α
F
. The Trace-0 hyperplane H 1 , is denoted
of
simply by H . Obviously for all α
F , H α = α 1 H .Notethat
F
is the union of
F 2 m = k|m C k ,where
cyclotomic cosets of length k whenever k
|
m .Thatis:
C k is
C k := α∈ F ,|C α | = k C α .
the set of field elements in a cyclotomic coset of length k , i.e.
The cardinalities c k :=
|C k |
can be calculated as follows:
c 1 =2 ,
since
C 1 =
{
0 , 1
}
,
(1)
c k =2 k
c l .
(2)
l|k,l = k
When m is odd, the intersections of the Trace-0-hyperplane with the subfields
of
F 2 m have the following cardinalities:
Lemma 1. Let m be odd, k
|
m ,and H
F 2 k denote the intersection of the
hyperplane H with the subfield
F 2 k of
F 2 m .Then
=2 k− 1 .
|
H
F 2 k |
Moreover, the intersection with the cyclotomic cosets of length k is
c k
2 .
|H ∩C k | =
(3)
Proof. Let α
F 2 k F 2 m .Then
Tr 1 ( α )= Tr 1 ( Tr k ( α )) = Tr 1 m
k α =
m
k Tr 1 ( α )= Tr 1 ( α ) .
=2 k− 1 . We prove the second claim by an easy induction on the
Hence
|
H
F 2 k |
+ e r of the prime decomposition m = p e 1
p e r r of m .
length l = e 1 +
···
···
If l =0,then H
F 2 =
{
0
}
,and
|
H
F 2 |
= c 1 / 2. Also for l =1,wehave
c m =2 m
=2 m− 1
2and
|
H
∩C k |
1. Now if all n
|
m , n
= m satisfy (3), then
we have (using (2))
c k
2
c m
2
=2 m− 1
|
H
∩C m |
=
,
k
|
m,k
= m
which was to be shown.
It is well known that the crosscorelation spectrum of Θ d is related to the cardi-
nality of intersections H d
αH if gcd ( d, q
1) = 1,
Θ d ( α )=
x∈ F
1) Tr ( x d + αx ) =
1) Tr ( x d )
1) Tr ( x d )
(
(
(
x∈α 1 H
x∈α 1 H
α 1 H
1) Tr ( x d ) =2 H d
=2
x∈α 1 H
α 1 H
H d
(
2 m +4 H d
α 1 H ,
=
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