Digital Signal Processing Reference
In-Depth Information
(a)
(b)
1
0.4
h ()
H ()
0.2
0.5
0
0
0
5
10
15
20
kf
=
50
50
-0.2
arg[
Hk
( )]
0
-0.4
-50
-0.6
0
5
10
15
20
0
5
10
15
20
n
kf
=
50
(c)
(d)
1.2
1.2
H ()
H ()
ω
ω
1
1
0.8
0.8
0.6
0.6
0.4
0.4
0.2
0.2
0
0
0
200
400
600
800
1000
0
200
400
600
800
1000
ωπ
2
ω2
Fig. 6.17 Characteristics of the high-pass filter designed with frequency response sampling
method (Example 6.11): a assumed filter frequency response b filter impulse response c effective
filter frequency response d frequency response after application of Hamming window
Applying
inverse
Fourier
transformation
results
in
the
following
filter
coefficients:
h ð 0 Þ¼ h ð 19 Þ¼ 0 : 0503; h ð 1 Þ¼ h ð 18 Þ¼ 0 : 0077; h ð 2 Þ¼ h ð 17 Þ¼ 0;
h ð 3 Þ¼ h ð 16 Þ¼ 0 : 0848;
h ð 4 Þ¼ h ð 15 Þ¼ 0 : 018; h ð 5 Þ¼ h ð 14 Þ¼ 0 : 088; h ð 6 Þ¼ h ð 13 Þ¼ 0 : 1162;
h ð 7 Þ¼ h ð 12 Þ¼ 0;
h ð 8 Þ¼ h ð 11 Þ¼ 0 : 4061; h ð 9 Þ¼ h ð 10 Þ¼ 0 : 3914;
In Fig. 6.17 b-d the filter impulse response along with corresponding filter
spectrum and spectrum after application of Hamming window are presented. All
remarks from preceding examples apply also to this case (spectrum oscillations,
effects of smoothing window, effects of higher number of filter coefficients), thus
they will not be repeated here again.
 
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