Civil Engineering Reference
In-Depth Information
Table 2.2.
Example 2.5 Cofactor method
1
1
1
1
10
A
=
8
4
2
1
C
=
26
-1
1
-1
1
2
3
2
1
0
10
4
2
1
8
2
1
8
4
1
8
4
2
A
=
1
1
1
1
1
+
1
1
1
1
1
−1
−
−1
−1
−1
−
−1
−1
2
1
0
3
1
0
3
2
0
3
2
1
A
=
3
+
0
+
−9
+
−6
A
=
−
12
4
2
1
8
2
1
8
4
1
8
4
2
(−1)
1+1
(−1)
1+2
(−1)
1+3
(−1)
1+4
c
11
=
1
-1
1
c
12
=
1
c
13
=
1
1
c
14
=
1
−1
−1
−1
−1
−1
2
1
0
3
1
0
3
2
0
3
2
1
c
11
= 3
c
12
= 0
c
13
= −9
c
14
= −6
1
1
1
1
1
1
1
1
1
1
1
1
(−1)
2+1
(−1)
2+2
(−1)
2+3
(−1)
2+4
c
21
=
1
1
c
22
=
1
c
23
=
1
1
c
24
=
1
−1
−1
−1
−1
−1
−1
2
1
0
3
1
0
3
2
0
3
2
1
c
22
= 4
c
23
= 4
c
21
= −4
c
24
= −4
1
1
1
1
1
1
1
1
1
1
1
1
(−1)
3+1
(−1)
3+2
(−1)
3+3
(−1)
3+4
c
31
=
4
2
1
c
32
=
8
2
1
c
33
=
8
4
1
c
34
=
8
4
2
2
1
0
3
1
0
3
2
0
3
2
1
c
31
= 1
c
33
= 5
c
32
= −4
c
34
= −2
1
1
1
(−1)
4+1
1
1
1
(−1)
4+2
1
1
1
(−1)
4+3
1
1
1
(−1)
4+4
c
41
=
4
2
1
c
42
=
8
2
1
c
43
=
8
4
1
c
44
=
8
4
2
1
1
1
1
1
-1
1
-1
−1
−1
−1
−1
c
41
= 6
c
44
= 12
c
42
= −12
c
43
= −6
3
0
3
1
6
−9
−6
−4
C
=
4
4
C
T
=
0
4
−4
−4
−4
−12
1
5
4
5
−4
−2
−9
−6
6
−12
−6
12
−6
−4
−2
12
0.3333
1
−0.2500
−0.0833
−0.5000
=
0.0000
0.3333
1.0000
x
=
2
A−
1
−0.3333
0.7500
−0.3333
−0.4167
0.5000
3
0.5000
0.3333
0.1667
-1.0000
4