Civil Engineering Reference
In-Depth Information
Table 5.6.
Example 5.3 Member stiffness, member 3
K
L
2083.3
0.0
0.0
0.0
0.0
−
2083.3
0.0
135.6
6510.4
0.0
6510.4
−
135.6
0.0
6510.4
416666.7
0.0
208333.3
−
6510.4
0.0
0.0
2083.3
0.0
0.0
−
2083.3
0.0
0.0
135.6
−
135.6
−
6510.4
−
6510.4
0.0
6510.4
208333.3
0.0
−
6510.4
416666.7
a
6.12574E
-
17
1
0
0
0
0
6.12574E
-
17
0
0
0
0
−
1
0
0
1
0
0
0
0
0
0
6.12574E
-
17
1
0
0
0
0
6.12574E-17
0
−
1
0
0
0
0
0
1
a
T
6.12574E-17
−
1
0
0
0
0
1
6.12574E-17
0
0
0
0
0
0
1
0
0
0
0
0
0
6.12574E-17
−
1
0
0
0
0
1
6.12574E-17
0
0
0
0
0
0
1
K
G
135.6
0.0
0.0
−
6510.4
−
135.6
−
6510.4
0.0
2083.3
0.0
0.0
0.0
−
2083.3
0.0
416666.7
6510.4
0.0
208333.3
−
6510.4
0.0
6510.4
135.6
0.0
6510.4
−
135.6
0.0
0.0
0.0
2083.3
0.0
−
2083.3
0.0
208333.3
6510.4
0.0
416666.7
−
6510.4
The global joint loading is determined from Equation 4.35. In this case,
members 1 and 4 are loaded with a uniformly distributed load. The fixed-
end forces and moments due to the load must be calculated. Normally, the
fixed-end forces and moments are rotated into the global system before
they are placed in the global joint loading, but in this case the member is
already in the global system and no rotation is necessary (step 3). The load
matrix is in units of kips and inches (k-in).
