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In-Depth Information
Multiplying by 1 n k and dividing by n k to obtain the coordinates of the centroid of the
k th interpolated group gives its coordinates as
&
&
)
&
)
)
D 11
D 22
.
D KK
D 1 k
D 2 k
D Kk
(
(
+ 2
(
+
1
+ .
1
2
= 1 Y
y k
K
1
2
Now, by definition
hk =−
(
D hh +
D kk
2 D hk )
, so the above may be written as
&
&
)
)
&
&
)
)
1
2 D kk
1 k +
1 k
2 k
.
Kk
(
(
+ 1
+ = 1 Y
(
(
+ 1
+
1
2 k +
2 D kk
= 1 Y
y k
.
Kk +
K
K
1
2 D kk
where the constant column is eliminated because of the centring Y 1 = 0 .
The dimensions of the centroids y k are r
×
1, and if we combine all the K interpolated
centroids into Y K we obtain
= 1 Y
,
11
K
Y K
which may be written, again because of the centring, as
= 1 Y I
I
11
K
11
K
Y K
.
Finally,
I
I
11
K
11
K
= YY ,
therefore we have
= 1 Y ( YY ) = 1
( Y Y ) Y = Y .
Y K
So the interpolated centroids coincide with the group average positions given by Y .
5.8.2 A simple example of analysis of distance
Note that in this example, where we use Pythagorean distance, the AoD reduces to a
PCA of the group means. In this example, similar to our introductory AoD example, we
now have five groups and so no exact two-dimensional group mean representation. The
AoD methodology is actually redundant, although we can still use it as a motivation for
performing the permutation testing procedure discussed below.
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