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order in σ p to be
f 2 ( σ p )= 4
J 2
p
{
σ p } ,
Q p ) 2
σ p +
2 A ξ −J
( Q p )
}
K
( Q p )
{
2(
σ p ·
(2 . 1 . 42)
where Q p
( q )is
found at q = Q along the η -axis, or the other equivalent b -axes, with Q
being about one fourth of the distance to the Brillouin-zone boundary,
and
= Q p /Q p . In Pr and Nd, the maximum of
J
( q )
±K
( Q ) is negative. The transition between the paramagnetic phase
and a phase described by (2.1.40), with J p lying in the hexagonal plane,
then occurs when the coecient 2 A ξ −J
K
( Q ) vanishes, at which
temperature the corresponding factor for the c -component of the mo-
ments, 2 A ζ −J
( Q )+
K
( Q ), is still positive in Pr and Nd. Besides confining the
moments to the hexagonal planes,
K
( Q ) also removes the degeneracy
between the two states in which J p
is parallel or perpendicular to Q p .
With a negative
( Q ), the anisotropic coupling favours a longitudinal
ordering of the moments at T N ,with J p parallel to Q p .Justbelow T N ,
the magnitude of the ordered moments is determined by f 2 ( σ p ), together
with the fourth-order contributions. When the moments lie in the basal
plane ( B = B ξξ = B ηη = B ξη ), we obtain, from eqn (2.1.22),
f 4 ( σ p )= B 1
K
N
i
J i · J i 2
= BJ 4 8
σ p · σ p ) 2 .
(2 . 1 . 43)
σ p σ p +2(
σ p + 4
p
p = p
Introducing the effective order parameter σ , defined by σ 2 = p σ p ,we
obtain further:
f
J 2 2 A ξ −J
( Q ) σ 2 + 8
f 2 ( σ p )+ f 4 ( σ p )= 4
J 4 4 , (2 . 1 . 44)
assuming J p parallel to Q p along the three b -axes making an angle of
120 with each other ( Q p ·
K
( Q )+
Q p
= p ). Hence the free
energy, in this approximation, is independent of whether the ordering is
single-, double- or triple- Q . Instead of utilizing (2.1.22), we may appeal
to symmetry arguments, by which the fourth-order term may readily be
seen to have the general form
f 4 ( σ p )= u
p
=
1 / 2when p
v
p = p
σ p + 2
σ p σ p ,
(2 . 1 . 45 a )
σ p vectors remain at 120
(Bak and Lebech 1978). Introducing the parameter w
as long as the angles between the different
v
2 u ,wemay
write this:
f 4 ( σ p )= u
p
w
p = p
σ p 2 + 2
σ p σ p =( u + γw ) σ 4 ,
(2 . 1 . 45 b )
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