Biomedical Engineering Reference
In-Depth Information
Theorem 2.3.
Sequences
.v
N
/
N
2N
and
.
u
N
/
N
2N
are
relatively
compact
in
L
2
.0;T I L
2
.0;1//
and
L
2
.0;T I L
2
.
F
//
, respectively.
Proof.
We use Theorem
2.1
with q D 2,andX D L
2
. We verify that both
assumptions (i) and (ii) hold.
Assumption (i): To show that the sequences .v
N
/
N
2N
and .
u
N
/
N
2N
are rel-
atively compact in L
2
.0;1/ and L
2
.
F
/, respectively, we use Lemma
2.3
and
the compactness of the embeddings H
s
.
F
/! L
2
.
F
/ and H
s=2
.0;1/ ,!
L
2
.0;1/, respectively, for 0<s<1=2. Namely, from Lemma
2.3
we know
that sequences .
u
N
/
N
2N
and .v
N
/
N
2N
are uniformly bounded in L
2
.0;T I H
s
.
F
//
and L
2
.0;T I H
s=2
.0;1//, respectively, for 0<s<1=2. The compactness of the
embeddings H
s
.
F
/,! L
2
.
F
/ and H
s=2
.0;1/ ,! L
2
.0;1/ verify Assumption
(i)ofTheorem
2.1
.
Assumption (ii): We prove that the “integral equicontinuity,” stated in assumption
(ii) of Theorem
2.1
, holds for the sequence .v
N
/
N
2N
. Analogous reasoning can be
used for .
u
N
/
N
2N
. Thus, we want to show that for each ">0, there exists a ı>0
such that
2
k
h
v
N
v
N
k
L
2
.!
I
L
2
.0;1//
<";
8jhj <ı;independently of N 2
N
; (2.159)
where ! is an arbitrary compact subset of . Indeed, we will show that for each
">0, the following choice of ı:
ı WD minfdist.!;@/=2;"=.2C/g
provides the desired estimate, where C is the constant from Lemma
2.1
(indepen-
dent of N).
Let h be an arbitrary real number whose absolute value is less than ı.Wewantto
show that (
2.159
) holds for all t D T=N. This will be shown in two steps. First,
we will show that (
2.159
) holds for the case when t h (Case 1), and then for the
case when t < h (Case 2).
A short remark is in order: For a given ı>0, we will have t < ı for infinitely
many N, and both cases will apply. For a finite number of functions .v
N
/, we will,
however, have that t ı. For those functions (
2.159
) needs to be proved for all
t such that jhj <ı t, which falls into Case 1 below. Thus, Cases 1 and 2
cover all the possibilities.
Case 1:
t h
.
We calculate the shift by h to obtain (see Fig.
2.11
,left):
Z
jt
jt
h
kv
N
v
j
C
1
N
1
X
2
L
2
.!
I
L
2
.0;1//
2
L
2
.0;1/
k
h
v
N
v
N
k
k
N
j
D
1
N
1
X
j
D
1
kv
N
v
j
C
1
2
D h
k
L
2
.0;1/
hC<"=2<":
N
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