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and the expression Z 0 refers to the complex conjugate of the complex vector
Z 0 representing
the landmark configuration after the compression/dilation. The Procrustes superimposition
of
P z 0 Z 0 . To get the vectors that describe the uniform deformation, we just
subtract the starting position
Z 0 on
Z
is thus
Z
from
P z 0 Z 0 and then divide through by the magnitude of the
Z 0 2
deformation
λ
, yielding (
P
Z)/
λ
as the set of vectors describing the deformation.
z 0
Further Derivation of the Uniform Components
To find
P Z 0 for the
S 2 (
λ
) mapping (compression/dilation), we note that the numerator
of
P z 0 is:
X
ZZ 0 5
ð X j
1
iY j Þ 3 ð X j
2
i ð Y j
Y j ÞÞ
(5A.5)
j
which expands to:
X
X j 2
2
2
5
ð
iX j Y j
2
iX j
λ
Y j
1
iX j Y j
2 ð
iY j Þ
2 ð
iY j Þ
λÞ
(5A.6)
j
Because i 2
1 and the products of X j Y j sum to zero (under the alignment specified
earlier), we can simplify this to:
52
X
ð X j 1
Y j 1
Y j λÞ
5
(5A.7)
j
Now add the constraint that P j ð X j 1
Y j Þ 5
1 because we scaled the reference to unit
centroid size, and we have:
X
Y j
ZZ 0 5
1
(5A.8)
j
Now we simplify the denominator of
P z 0 :
X
Z 0 Z 0 5
ð X j
1
iY j ð 1
1λÞÞ 3 ð X j
2
iY j ð 1
1λÞÞ
(5A.9)
j
X
X
2
ð X j 1
Y j ð 1
X j 1
Y j ð 1
2
5
1λÞ
Þ 5
1
2
λ1λ
Þ
(5A.10)
j
j
X
X j 1
Y j 1
2Y j λ1
Y j λ
2
5
(5A.11)
j
As mentioned before, P j ð
X j 1
Y j Þ 5
2
1
;
and terms including
λ
can be discarded in the
limit of small
λ
, so that:
X
Z 0 Z 0 D
Y j
1
1
2
λ
(5A.12)
j
This leaves us with:
P j Y j Þ
ð 1
ZZ 0
Z 0 Z 0 5
Pz 0
λ P j Y j Þ
5
(5A.13)
ð 1
1
2
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