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• t s
convex
, and
• t s
Cauchy closed
, that is, it contains all its limit points in the usual Euclidean
metric, and is
bounded
.
1
We are now ready to generalise Proposition
4.1
in order to compare two sets of
vectors. Here we require one set to be
p
-closed, which allows us to appeal to the
separation theorem from discrete geometry (cf. Theorem 2.7); Cauchy closure alone
is not enough.
Let A
,
B be subsets of
[0, 1]
n
; then we have
Theorem 4.1
:
h
h
[0, 1]
n
A
≤
Ho
B iff
∀
h
∈
·
A
≤
·
B
if B is p-closed, and
[0, 1]
n
A
≤
Sm
B iff
∀
h
∈
:
h
·
A
≤
h
·
B
if A is p-closed.
Proof
We consider first the
only-if
direction for the Smyth case:
≤
Sm
B
A
iff
∀
b
∈
B
:
∃
a
∈
A
:
a
≤
b
Definition of
≤
Ho
[0, 1]
n
implies
∀
h
∈
:
∀
b
∈
B
:
∃
a
∈
A
:
h
·
a
≤
h
·
b
h
≥
0
[0, 1]
n
implies
∀
h
∈
:
∀
b
∈
B
:
h
·
A
≤
h
·
b
h
·
A
≤
h
·
a
∀
∈
[0, 1]
n
·
≤
·
implies
h
:
h
A
h
B
Definition of infimum
.
For the
if
-direction, we use separating hyperplanes, proving the contrapositive:
A
≤
Sm
B
iff
∀
a
∈
A
:
¬
(
a
≤
b
)
Definition of
≤
Sm
; for some
b
∈
B
B
=∅
define
B
:
b
∈ R
n
b
≤
iff
A
∩
={
|
b
}
n
,
c
∈ R
iff
∃
h
∈ R
:
A
,
b
∈
B
:
∀
a
∈
b
<c<h
h
·
·
a.
In the last step of the reasoning above, we have used Theorem 2.7 as
A
is
p
-closed and
B
is convex and Cauchy closed by construction; see Fig.
4.2
. Moreover, without loss
of generality, the inequality can be in the direction shown, else we simply multiply
h
,
c
by
1.
We now argue that
h
is nonnegative, whence by scaling of
h
,
c
we obtain without
loss of generality that
h
−
[0, 1]
n
. Assume for a contradiction that
h
i
<
0. Choose
∈
1
Cauchy closure and boundedness together amount to
compactness
.
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