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• t s convex , and
• t s Cauchy closed , that is, it contains all its limit points in the usual Euclidean
metric, and is bounded . 1
We are now ready to generalise Proposition 4.1 in order to compare two sets of
vectors. Here we require one set to be p -closed, which allows us to appeal to the
separation theorem from discrete geometry (cf. Theorem 2.7); Cauchy closure alone
is not enough.
Let A , B be subsets of [0, 1] n ; then we have
Theorem 4.1
: h
h
[0, 1] n
A
Ho B iff
h
·
A
·
B
if B is p-closed, and
[0, 1] n
A
Sm B iff
h
:
h
·
A
h
·
B
if A is p-closed.
Proof
We consider first the only-if direction for the Smyth case:
Sm B
A
iff
b B :
a A : a b
Definition of
Ho
[0, 1] n
implies
h
:
b
B :
a
A : h
·
a
h
·
b
h
0
[0, 1] n
implies
h
:
b
B :
h
·
A
h
·
b
h
·
A
h
·
a
[0, 1] n
·
·
implies
h
:
h
A
h
B
Definition of infimum .
For the if -direction, we use separating hyperplanes, proving the contrapositive:
A
Sm B
iff
a
A :
¬
( a
b )
Definition of
Sm ; for some b
B
B =∅
define B :
b ∈ R
n
b
iff
A
={
|
b
}
n , c ∈ R
iff
h ∈ R
:
A , b
B :
a
b <c<h
h
·
·
a.
In the last step of the reasoning above, we have used Theorem 2.7 as A is p -closed and
B is convex and Cauchy closed by construction; see Fig. 4.2 . Moreover, without loss
of generality, the inequality can be in the direction shown, else we simply multiply
h , c by
1.
We now argue that h is nonnegative, whence by scaling of h , c we obtain without
loss of generality that h
[0, 1] n . Assume for a contradiction that h i < 0. Choose
1
Cauchy closure and boundedness together amount to compactness .
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