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a) We have ʔ = ( s , t ) I p ( s , t ) · s because, for any s S ,
( s , t ) I p ( s , t ) ·
s ( s )
( s , t ) I w ( s , t )
=
=
{
w ( s , t )
|
w ( s , t ) > 0, t
T
}
=
{
w ( s , t )
|
t
T
}
=
ʔ ( s ) .
= ( s , t ) I
b) Similarly, we have ʘ
w ( s , t )
·
t .
c) For each ( s , t )
I ,wehave w ( s , t ) > 0, which implies s
R
t .
Hence, the above decompositions of ʔ and ʘ meet the requirement of the lifting
ʔ
ʘ .
R
ʘ . By Propos it ion 3.1 , we can decompose ʔ and ʘ such that
2. (
) Suppose ʔ
R
= i I p i ·
= i I p i ·
ʔ
s i , ʘ
t i , and s i R
t i for all i
I . For any equivalence
class C
S/
R
, we have that
s C ʔ ( s )
s C
ʔ ( C )
=
=
{
p i |
i
I , s i =
s
}
=
{
p i |
i
I , s i
C
}
=
{
p i |
i
I , t i
C
}
=
ʘ ( C )
where the equality in the third line is justified by the fact that s i C iff t i C
since s i R t i and C S/ R
.
(
) Suppose ʔ ( C )
=
ʘ ( C ) for each equivalence class C
S/
R
. We construct
ʔ ( s ) ʘ ( t )
ʔ ([ s ])
the index set I
={
( s , t )
|
s
R
t and s , t
S
}
and probabilities p ( s , t ) =
for
each ( s , t )
I , where [ s ] stands for the equivalence class that contains s .
= ( s , t ) I p ( s , t ) ·
s because, for any s
a) We have ʔ
S ,
( s , t ) I p ( s , t ) ·
s ( s )
( s , t ) I p ( s , t )
=
ʔ ( s ) ʘ ( t )
ʔ ([ s ]) |
S
s R
=
t , t
ʔ ( s ) ʘ ( t )
ʔ ([ s ]) |
[ s ]
=
t
ʔ ([ s ])
ʔ ( s )
[ s ]
=
{ ʘ ( t )
| t
}
ʔ ( s )
ʔ ([ s ]) ʘ ([ s ])
=
 
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