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a) We have
ʔ
=
(
s
,
t
)
∈
I
p
(
s
,
t
)
·
s
because, for any
s
∈
S
,
(
s
,
t
)
∈
I
p
(
s
,
t
)
·
s
(
s
)
(
s
,
t
)
∈
I
w
(
s
,
t
)
=
=
{
w
(
s
,
t
)
|
w
(
s
,
t
)
>
0,
t
∈
T
}
=
{
w
(
s
,
t
)
|
t
∈
T
}
=
ʔ
(
s
)
.
=
(
s
,
t
)
∈
I
b) Similarly, we have
ʘ
w
(
s
,
t
)
·
t
.
c) For each (
s
,
t
)
∈
I
,wehave
w
(
s
,
t
)
>
0, which implies
s
R
t
.
Hence, the above decompositions of
ʔ
and
ʘ
meet the requirement of the lifting
ʔ
†
ʘ
.
R
†
ʘ
. By Propos
it
ion
3.1
, we can decompose
ʔ
and
ʘ
such that
2. (
⃒
) Suppose
ʔ
R
=
i
∈
I
p
i
·
=
i
∈
I
p
i
·
ʔ
s
i
,
ʘ
t
i
, and
s
i
R
t
i
for all
i
∈
I
. For any equivalence
class
C
∈
S/
R
, we have that
s
∈
C
ʔ
(
s
)
s
∈
C
ʔ
(
C
)
=
=
{
p
i
|
i
∈
I
,
s
i
=
s
}
=
{
p
i
|
i
∈
I
,
s
i
∈
C
}
=
{
p
i
|
i
∈
I
,
t
i
∈
C
}
=
ʘ
(
C
)
where the equality in the third line is justified by the fact that
s
i
∈
C
iff
t
i
∈
C
since
s
i
R
t
i
and
C
∈
S/
R
.
(
⃐
) Suppose
ʔ
(
C
)
=
ʘ
(
C
) for each equivalence class
C
∈
S/
R
. We construct
ʔ
(
s
)
ʘ
(
t
)
ʔ
([
s
])
the index set
I
={
(
s
,
t
)
|
s
R
t
and
s
,
t
∈
S
}
and probabilities
p
(
s
,
t
)
=
for
each (
s
,
t
)
∈
I
, where [
s
] stands for the equivalence class that contains
s
.
=
(
s
,
t
)
∈
I
p
(
s
,
t
)
·
s
because, for any
s
∈
a) We have
ʔ
S
,
(
s
,
t
)
∈
I
p
(
s
,
t
)
·
s
(
s
)
(
s
,
t
)
∈
I
p
(
s
,
t
)
=
ʔ
(
s
)
ʘ
(
t
)
ʔ
([
s
])
|
S
s
R
=
t
,
t
∈
ʔ
(
s
)
ʘ
(
t
)
ʔ
([
s
])
|
[
s
]
=
∈
t
ʔ
([
s
])
ʔ
(
s
)
[
s
]
=
{
ʘ
(
t
)
|
t
∈
}
ʔ
(
s
)
ʔ
([
s
])
ʘ
([
s
])
=
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