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or
for all x
∈
X and y
∈
Y , we have h
·
x>c>h
·
y .
n
Here the hyperplane is a set of the form
{
z
∈ R
|
h
·
z
=
c
}
.
Definition 2.18
Let (
X
,
d
) be a metric space. A function
f
:
X
ₒ
X
is said to be
a
contraction mapping
if there is a constant
ʴ
with 0
≤
ʴ<
1 such that
d
(
f
(
x
),
f
(
y
))
≤
ʴ
·
d
(
x
,
y
)
for all
x
,
y
X
.
In the above definition, the constant
ʴ
is strictly less than 1. It entails the following
property whose proof crucially relies on that constraint on
ʴ
and is worth writing
down.
∈
Theorem 2.8 (Banach Fixed-Point Theorem)
Every contraction on a complete
metric space has a unique fixed point.
Proof
Let (
X
,
d
) be a complete metric space, and
f
be a contraction mapping on
(
X
,
d
) with constant
ʴ
. For any
x
0
∈
=
X
, define the sequence (
x
n
)by
x
n
+
1
:
f
(
x
n
)
for
n
≥
0. Let
a
:
=
d
(
x
0
,
x
1
). It is easy to show that
≤
ʴ
n
d
(
x
n
,
x
n
+
1
)
·
a
by repeated application of the property
d
(
f
(
x
),
f
(
y
))
≤
ʴ
·
d
(
x
,
y
). For any
ʵ>
0,
ʴ
n
it is possible to choose a natural number
N
such that
1
−
ʴ
a<ʵ
for all
n
≥
N
.Now,
for any
m
,
n
≥
N
with
m
≤
n
,
d
(
x
m
,
x
n
)
≤
d
(
x
m
,
x
m
+
1
)
+
d
(
x
m
+
1
,
x
m
+
2
)
+···+
d
(
x
n
−
1
,
x
n
)
ʴ
m
ʴ
m
+
1
ʴ
n
−
1
≤
·
a
+
·
a
+···+
·
a
ʴ
m
1
−
ʴ
n
−
m
1
−
ʴ
=
a
ʴ
m
<
1
−
ʴ
a<ʵ
by repeated application of the triangle inequality. So the sequence (
x
n
) is a Cauchy
sequence. Since (
X
,
d
) is complete, the sequence has a limit in (
X
,
d
). We define
x
∗
to be this limit and show that it is a fixed point of
f
. Suppose it is not, i.e.
a
∗
:
d
(
x
∗
,
f
(
x
∗
))
>
0. Since (
x
n
) converges to
x
∗
, there exists some
N
=
∈ N
such
that
d
(
x
n
,
x
∗
)
<
a
2
for all
n
≥
N
. Then
d
(
x
∗
,
f
(
x
∗
))
d
(
x
∗
,
x
N
+
1
)
d
(
x
N
+
1
,
f
(
x
∗
))
≤
+
d
(
x
∗
,
x
N
+
1
)
d
(
x
N
,
x
∗
)
≤
+
ʴ
·
a
2
+
a
2
=
a
∗
,
<
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