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symmetric to that used in part (i) we can show that this implies the existence
of some ʔ such that ʔ
˄
ʔ , that is s
˄
ʔ and ʘ (
bis ) ʔ .
s ) do not coincide for arbitrary distributions.
For example, consider the two processes P = a. 0 2 b. 0 and Q = P P . It is easy
to see that [[ P ]]
But in general the relations
and (
s )
[[ Q ]] b u t n o t [[ P ]] (
[[ Q ]]; the latter follows because the point
1
1
distribution [[ Q ]] cannot be decomposed as
2 ·
ʘ a +
2 ·
ʘ b for some ʘ a and ʘ b so
that [[ a. 0 ]]
s ʘ b .
The nearest to a general converse to Theorem 7.3 is the following:
s ʘ a and [[ b. 0 ]]
ʘ in a finitary pLTS. Then there is some ʘ with
Proposition 7.3
Suppose ʔ
˄
s ) ʘ .
Proof Now suppose ʔ
ʘ and ʔ (
ʘ
ʘ . We can rewrite ʔ as s ʔ
ʔ ( s )
·
s , and the reflexivity
s ʔ
˄
˄
of
gives ʔ
ʔ ( s )
·
s . Since
is a bisimulation, this move can be
ʘ = s ʔ
˄
matched by some ʘ
ʔ ( s )
·
ʘ s such that s
ʘ s . But we have
just shown in the previous proposition that this means s
s ʘ s .
ʱ
s ) ʘ and therefore ʘ
ʘ is the required move.
By Definition 6.2, ʔ (
from Definition 7.1 , is our primary behavioural equiv-
alence but we will often develop properties of it via the connection we have just
established with
The weak bisimilarity,
s from Definition 7.2 ; the latter is more amenable as it only re-
quired strong moves to be matched. However, we can also prove properties of
s by
using this connection to weak bisimilarity; a simple example is the following:
˄
s ʘ in a finitary pLTS, where s
−ₒ
Corollary 7.2
Suppose s
. Then whenever
˄
ʘ it follows that s
s ʘ .
ʘ
s )
Proof
Suppose s
s ʘ , which means s (
ʘ and therefore by Theorem 7.3
˄
ʘ must be matched by a corresponding m ove from s .
s
ʘ . The move ʘ
˄
ʘ .Now
However, since s
−ₒ
the only possibility is the empty move, giving s
by Proposition 7.2 , we have the required s s ʘ .
Corollary 7.3
In any finitary pLTS, the relation
is linear.
Consider any collection of probabilities p i with i I p i =
Proof
1, where I is a
finite index set. Suppose further that ʔ i
ʘ i for each i
I . We need to show that
= i I p i ·
= i I p i ·
ʔ
ʘ , where ʔ
ʔ i and ʘ
ʘ i .
˄
By Proposition 7.3 , there is some ʘ i
ʘ i
s )
ʘ i .By
with ʘ i
and ʔ i (
˄
s )
Theorem 6.6 (i) and Definition 6.2, both
and (
are linear. Therefore, we
ʘ , where ʘ = i I p i ·
˄
ʘ and ʔ (
s )
ʘ i . It follows from
have ʘ
ʘ .
Now for any transition ʔ
Theorem 7.3 that ʔ
( j J q j ·
ʱ
ʔ j ), where J is finite, there is a
( j J q j ·
ʱ
matching transition ʘ
ʘ j ) such that ʔ j
ʘ j for each j
J . Note
( j J q j ·
ʱ
that we also have the transition ʘ
ʘ j ) according to the transitivity
( j J q j ·
˄
ʱ
of
. By symmetrical arguments, any transition ʘ
ʘ j ) can be
( j J q j ·
ʱ
matched by some transition ʔ
ʔ j ) such that ʔ j
ʘ j for each
 
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