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symmetric to that used in part (i) we can show that this implies the existence
of some
ʔ
such that
ʔ
˄
⃒
ʔ
, that is
s
˄
⃒
ʔ
and
ʘ
(
bis
)
†
ʔ
.
≈
≈
s
)
†
do not coincide for arbitrary distributions.
For example, consider the two processes
P
=
a.
0
2
↕
b.
0
and
Q
=
P
P
. It is easy
to see that [[
P
]]
But in general the relations
≈
and (
≈
s
)
†
≈
[[
Q
]] b u t n o t [[
P
]] (
[[
Q
]]; the latter follows because the point
1
1
distribution [[
Q
]] cannot be decomposed as
2
·
ʘ
a
+
2
·
ʘ
b
for some
ʘ
a
and
ʘ
b
so
that [[
a.
0
]]
≈
s
ʘ
b
.
The nearest to a general converse to Theorem
7.3
is the following:
≈
s
ʘ
a
and [[
b.
0
]]
ʘ in a finitary pLTS. Then there is some ʘ
with
Proposition 7.3
Suppose ʔ
≈
˄
⃒
≈
s
)
†
ʘ
.
Proof
Now suppose
ʔ
ʘ
and ʔ
(
ʘ
ʘ
. We can rewrite
ʔ
as
s
∈
ʔ
≈
ʔ
(
s
)
·
s
, and the reflexivity
⃒
s
∈
ʔ
˄
⃒
˄
of
gives
ʔ
ʔ
(
s
)
·
s
. Since
≈
is a bisimulation, this move can be
ʘ
=
s
∈
ʔ
˄
⃒
matched by some
ʘ
ʔ
(
s
)
·
ʘ
s
such that
s
≈
ʘ
s
. But we have
just shown in the previous proposition that this means
s
≈
s
ʘ
s
.
ʱ
⃒
≈
s
)
†
ʘ
and therefore
ʘ
ʘ
is the required move.
By Definition 6.2,
ʔ
(
from Definition
7.1
, is our primary behavioural equiv-
alence but we will often develop properties of it via the connection we have just
established with
The weak bisimilarity,
≈
≈
s
from Definition
7.2
; the latter is more amenable as it only re-
quired strong moves to be matched. However, we can also prove properties of
≈
s
by
using this connection to weak bisimilarity; a simple example is the following:
˄
≈
s
ʘ in a finitary pLTS, where s
−ₒ
Corollary 7.2
Suppose s
. Then whenever
˄
⃒
ʘ
it follows that s
≈
s
ʘ
.
ʘ
≈
s
)
†
Proof
Suppose
s
≈
s
ʘ
, which means
s
(
ʘ
and therefore by Theorem
7.3
˄
⃒
≈
ʘ
must be matched by a corresponding
m
ove from
s
.
s
ʘ
. The move
ʘ
˄
ʘ
.Now
However, since
s
−ₒ
the only possibility is the empty move, giving
s
≈
by Proposition
7.2
, we have the required
s
≈
s
ʘ
.
Corollary 7.3
In any finitary pLTS, the relation
≈
is linear.
Consider any collection of probabilities
p
i
with
i
∈
I
p
i
=
Proof
1, where
I
is a
finite index set. Suppose further that
ʔ
i
≈
ʘ
i
for each
i
∈
I
. We need to show that
=
i
∈
I
p
i
·
=
i
∈
I
p
i
·
ʔ
≈
ʘ
, where
ʔ
ʔ
i
and
ʘ
ʘ
i
.
˄
⃒
By Proposition
7.3
, there is some
ʘ
i
ʘ
i
≈
s
)
†
ʘ
i
.By
with
ʘ
i
and
ʔ
i
(
˄
⃒
≈
s
)
†
Theorem 6.6 (i) and Definition 6.2, both
and (
are linear. Therefore, we
ʘ
, where
ʘ
=
i
∈
I
p
i
·
˄
⃒
ʘ
and
ʔ
(
≈
s
)
†
ʘ
i
. It follows from
have
ʘ
ʘ
.
Now for any transition
ʔ
Theorem
7.3
that
ʔ
≈
(
j
∈
J
q
j
·
ʱ
⃒
ʔ
j
), where
J
is finite, there is a
(
j
∈
J
q
j
·
ʱ
⃒
matching transition
ʘ
ʘ
j
) such that
ʔ
j
≈
ʘ
j
for each
j
∈
J
. Note
(
j
∈
J
q
j
·
ʱ
⃒
that we also have the transition
ʘ
ʘ
j
) according to the transitivity
(
j
∈
J
q
j
·
˄
⃒
ʱ
⃒
of
. By symmetrical arguments, any transition
ʘ
ʘ
j
) can be
(
j
∈
J
q
j
·
ʱ
⃒
matched by some transition
ʔ
ʔ
j
) such that
ʔ
j
≈
ʘ
j
for each
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