Information Technology Reference
In-Depth Information
2. 0 A
d ( ˄.ˉ , ʔ ) iff ʔ
ʵ.
3. 0 A
A
d (
.
4. Suppose the action ˉ does not occur in the test T . Then o
a X a.ˉ , ʔ ) iff ʔ
−ₒ
d ( ˄.ˉ
A
a.T , ʔ )
a
0 iff there is a ʔ D sub ( sCSP) with ʔ
ʔ and o
d ( T , ʔ ) .
with o ( ˉ )
=
A
d ( T 1 p
d ( T i , ʔ ) .
5. o
A
T 2 , ʔ ) iff o
=
p
·
o 1 +
(1
p )
·
o 2 for certain o i A
d ( T 1
6. o
A
T 2 , ʔ ) if there are a q
[0, 1] and ʔ 1 , ʔ 2 D sub ( sCSP) such that
d ( T i , ʔ i ) .
ʔ
q
·
ʔ 1 +
(1
q )
·
ʔ 2 and o
=
q
·
o 1 +
(1
q )
·
o 2 for certain o i A
ˉ
−ₒ
Proof
, the states in the support of [ ˉ | Act ʔ ] have no other
outgoing transitions than ˉ . Therefore, [ ˉ | Act ʔ ] is the unique extreme derivative of
itself, and as $[ ˉ
1. Since ˉ | Act ʔ
ˉ we have
d ( ˉ , ʔ )
| Act ʔ ]
=|
ʔ
A
={|
ʔ
ˉ
}
.
2. (
| Act ʵ .
All states involved in this derivation (that is, all states u in the support of the
intermediate distributions ʔ i
) Assume ʔ
ʵ . By Lemma 6.27 (1), we have ˄.ˉ
| Act ʔ
˄.ˉ
and ʔ i
of Definition 6.4 ) must have the form
ˉ
˄.ˉ
| Act s , and thus satisfy u
−ₒ
for all ˉ
ʩ . Therefore, it follows that
[ ˄.ˉ
| Act ʔ ]
[ ˄.ˉ
| Act ʵ ]. Trivially, [ ˄.ˉ
| Act ʵ ]
=
ʵ is stable, and hence an
0 ,so 0 A
d ( ˄.ˉ , ʔ ).
extreme derivative of [ ˄.ˉ
| Act ʔ ]. Moreover, $ ʵ
=
) Suppose 0
d ( ˄.ˉ , ʔ ), that is, there is some extreme derivative ʓ of
(
A
0 . Given the operational semantics of rpCSP , all
[ ˄.ˉ
| Act ʔ ] such that $ ʓ
=
states u
ʓ
must have one of the forms u
=
[ ˄.ˉ
| Act t ]or u
=
[ ˉ
| Act t ].
0 , the latter possibility cannot occur. It follows that all transitions
contributing to the derivation [ ˄.ˉ | Act ʔ ]
As $ ʓ
=
ʓ do not require any action
| Act ʔ ] for some distribution ʔ with
from ˄.ˉ , and, in fact, ʓ has the form [ ˄.ˉ
ʔ .As ʓ must be stable, yet none of the states in its support are, it follows
ʔ
, that is, ʔ =
that
ʓ
=∅
ʵ .
3. Let T :
= a X a.ˉ .
X
| Act ʔ by
Lemma 6.27 (1), and by the same argument as in the previous case, we have
[ T
ʔ
for some ʔ . Then, T
(
) Assume ʔ
−ₒ
| Act ʔ
T
| Act ʔ ]. All states in the support of T
| Act ʔ are deadlocked. So
| Act ʔ ]
[ T
0 . Thus, we have 0 A
d ( T , ʔ ).
[ T
| Act ʔ ]
[ T
| Act ʔ ] and $( T
| Act ʔ )
=
) Suppose 0
d ( T , ʔ ). By the very same reasoning as in Case 2 we find
(
A
X
ʔ for some ʔ such that T
| Act ʔ is stable. This implies ʔ
.
4. Let T be a test in which the success action ˉ does not occur, and let U be an
abbreviation for ˄.ˉ
that ʔ
−ₒ
a.T .
a
) Assume there is a ʔ D sub ( sCSP ) with ʔ
ʔ and o
d ( T , ʔ ).
(
A
a
−ₒ
ʔ .
Using Lemma 6.27 (1) and (3), and the same reasoning as in the previous cases,
[ U
ʔ pre
ʔ post
Without loss of generality we may assume that ʔ
˄
−ₒ
| Act ʔ ]
| Act ʔ pre ]
| Act ʔ post ]
| Act ʔ ]
[ U
[ T
[ T
ʓ for a stable
=
A
d ( U , ʔ ).
subdistribution ʓ with $ ʓ
o . It follows that o
(
) Suppose o
A
d ( U , ʔ ) with o ( ˉ )
=
0. Then, there is a stable subdistribution
ʓ such that [ U
| Act ʔ ]
ʓ and $ ʓ
=
o . Since o ( ˉ )
=
0, there is no state in
Search WWH ::




Custom Search