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˄
−ₒ⃒ ʓ ʵ ,
(a) s | A t
˄
−ₒ⃒
ʨ .
(b) ʘ
| A t
ʨ and ʓ
R
˄
−ₒ p ʓ
By Lemma 6.29 , there are ʔ , ʓ
ʔ and ʔ | A t
D sub ( S ) with s
ʵ .
FS coincides with
FS and
e FS by Lemma 6.26 and
Since for finitary processes
FS ) ʘ .
Theorem 6.12 , there must be a ʘ D sub ( S ) such that ʘ
ʘ and ʔ (
C
˄
−ₒ⃒ ʨ for some ʨ such that ʓ
By Proposition 6.10 ,wehave ʘ | A t
ʨ .
R
˄
−ₒ
˄
−ₒ⃒
ʔ | A t
ʘ | A t
Now, s
| A t
ʓ
ʵ and ʘ
| A t
ʨ with
ʨ , which had to be shown.
Therefore, we have shown that
ʓ
R
FS . Now let us focus our attention on the
statement of the proposition, which involves
R
FS .
FS ʔ . By Proposition 6.7 , this means that there is some ʘ match
Suppose ʘ
such
e FS )
ʘ match
ʘ match . By Theorem 6.12 and Lemma 6.26 ,we
that ʘ
and ʔ (
FS ) ʘ match . Then Lemma 6.27 (5) yields ( ʔ
C
( ʘ match
have ʔ (
| A Φ )
R
| A Φ ). There-
FS )
C
( ʘ match
e
FS )
( ʘ match
fore, we have ( ʔ
| A Φ )
by Lemma 6.26 and Theorem 6.12 . By using Lemma 6.27 (1), we also have that
( ʘ
| A Φ )(
| A Φ ), that is, ( ʔ
| A Φ )(
( ʘ match
| A Φ )
| A Φ ), which had to be established according to Proposi-
tion 6.7 .
e
FS
S
In the proof of Proposition 6.11 , we use the characterisation of
as
FS ,
S
FS
which assumes the pLTS to be finitary. In general, the relation
is not closed
under parallel composition.
Example 6.23 We use a modification of the infinite state pLTS's in Example 6.5
that as before has states s k with k
2, but we add an extra a -looping state s a to give
all together the system
˄
−ₒ
a
−ₒ s a .
for k
2
s k
( s a
k 2 s k + 1 )
and
s a
1
FS
There is a failure simulation so that s k
( s a k
0 ) because from state s k the
˄
−ₒ
transition s k
( s a k 2
s k + 1 ) can be matched by a transition to ( s a k 2
( s a 1
k +
0 ))
1
that simplifies to just ( s a k
0 ) again, that is, a sufficient simulating transition would
be the identity instance of
.
Now s 2 | { a } s a wholly di verges even th ough s 2 itself does not, and (recall from
above)wehave s 2
S
FS
( s a 2
0 ). Yet ( s a 2
0 )
| { a } s a does not diverge, and therefore
S
FS
s 2 | { a } s a
| { a } S a .
Note that this counter-example does not go through if we us e failure similarity
( S a 2
0 )
e
S
e
FS instead of simple failure similarity
FS , since s 2
FS ( s a 2
0 )—the former
has the transition s 2
s a 2
ʵ , which cannot be matched by s a 2
0 .
Proposition 6.12 (Precongruence) In a finitary pLTS, if P
FS Q then it holds
FS ʱ.Q for any ʱ
Act , and similarly if P 1 FS Q 1 and P 2 FS Q 2 then
that ʱ.P
P 1
P 2 FS Q 1
, p
| A .
Q 2 for
being any of the operators
,
and
 
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