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ʔ =
ʔ × =
p i · s i ,
p i · s i
i ( I J )
i J
ʔ next
ʓ i ,
ʓ × =
=
p i ·
p i ·
ʓ i
i ( I J )
i J
By construction (i) and (iv) are satisfied, and (ii) and (iii) follow by property (2) of
Definition 6.2 .
ʵ then there is a ʔ D sub ( S ) such that ʔ
ʔ and
Lemma 6.29
If ʔ
| A t
˄
−ₒ p
ʔ | A t
ʵ.
Proof
Suppose ʔ 0 | A t
ʵ . By Lemma 6.24 there is an infinite sequence
˄
−ₒ
˄
−ₒ
˄
−ₒ
ʔ 0 | A t
ʨ 1
ʨ 2
...
(6.23)
0, we find distributions ʓ k + 1 , ʔ k
, ʔ k , ʔ k + 1 , ʓ k + 1 such that
By induction on k
˄
−ₒ
(i) ʔ k | A t
ʓ k + 1
(ii) ʓ k + 1
ʨ k + 1
ʔ k
ʔ k
(iii) ʔ k =
+
˄
−ₒ ʔ k + 1
(v) ʔ k | A t
(iv) ʔ k
˄
−ₒ p ʓ k + 1
ʓ k + 1 .
Induction Base Take ʓ 1 :
(vi) ʓ k + 1 =
ʔ k + 1 | A t
+
ʨ 1 and apply Lemma 6.28 .
Induction Step Assume we already have ʓ k , ʔ k and ʓ k
=
. Since ʔ k | A t ʓ k ʨ k
˄
−ₒ
˄
−ₒ
and ʨ k
ʨ k + 1 , Proposition 6.2 givesusa ʓ k + 1 such that ʔ k | A t
ʓ k + 1 and
ʓ k + 1
ʨ k + 1 . Now apply Lemma 6.28 .
Let ʔ :
= k = 0 ʔ k .
By (iii) and (iv) above,
we obtain a weak ˄ move
= k = 0 ( ʔ k | A t ), by (v) and Definition 6.2 we have
ʔ 0
ʔ . Since ʔ | A t
−ₒ p k = 1 ʓ k
˄
ʔ | A t
Note that here it does not matter if ʔ
.
=
ʵ .
Since
ʓ k
ʵ , it follows from Theorem 6.5 (ii) that ʓ k
ʓ k
ʨ k and ʨ k
ʵ .
Hence by using Theorem 6.5 (i), we obtain that k = 1 ʓ k
ʵ .
We are now ready to prove the main result of this section, namely that
FS is
preserved by the parallel operator.
FS ʔ then ʘ
| A Φ
FS ʔ
| A Φ.
Proposition 6.11
In a finitary pLTS, if ʘ
Proof
We first construct the following relation
C
R
:
={
( s
| A t , ʘ
| A t )
|
s
FS ʘ
}
FS . As in the proof of Theorem 5.1, one can check that
each strong transition from s
and check that
R
| A t , and the
matching of failures can also be established. So we concentrate on the requirement
involving divergence.
Suppose s
| A t can be matched by a transition from ʘ
FS ʘ and s | A t ʵ . We need to find some ʓ , ʨ such that
 
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