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ʔ
ₒ
=
ʔ
×
=
p
i
·
s
i
,
p
i
·
s
i
i
∈
(
I
−
J
)
i
∈
J
ʔ
next
ʓ
i
,
ʓ
×
=
=
p
i
·
p
i
·
ʓ
i
i
∈
(
I
−
J
)
i
∈
J
By construction (i) and (iv) are satisfied, and (ii) and (iii) follow by property (2) of
Definition
6.2
.
ʵ then there is a ʔ
∈
D
sub
(
S
)
such that ʔ
ʔ
and
Lemma 6.29
If ʔ
|
A
t
⃒
⃒
˄
−ₒ
p
⃒
ʔ
|
A
t
ʵ.
Proof
Suppose
ʔ
0
|
A
t
⃒
ʵ
. By Lemma
6.24
there is an infinite sequence
˄
−ₒ
˄
−ₒ
˄
−ₒ
ʔ
0
|
A
t
ʨ
1
ʨ
2
...
(6.23)
0, we find distributions
ʓ
k
+
1
,
ʔ
k
,
ʔ
k
,
ʔ
k
+
1
,
ʓ
k
+
1
such that
By induction on
k
≥
˄
−ₒ
(i)
ʔ
k
|
A
t
ʓ
k
+
1
(ii)
ʓ
k
+
1
≤
ʨ
k
+
1
ʔ
k
ʔ
k
(iii)
ʔ
k
=
+
˄
−ₒ
ʔ
k
+
1
(v)
ʔ
k
|
A
t
(iv)
ʔ
k
˄
−ₒ
p
ʓ
k
+
1
ʓ
k
+
1
.
Induction Base
Take
ʓ
1
:
(vi)
ʓ
k
+
1
=
ʔ
k
+
1
|
A
t
+
ʨ
1
and apply Lemma
6.28
.
Induction Step
Assume we already have
ʓ
k
,
ʔ
k
and
ʓ
k
=
. Since
ʔ
k
|
A
t
≤
ʓ
k
≤
ʨ
k
˄
−ₒ
˄
−ₒ
and
ʨ
k
ʨ
k
+
1
, Proposition
6.2
givesusa
ʓ
k
+
1
such that
ʔ
k
|
A
t
ʓ
k
+
1
and
ʓ
k
+
1
≤
ʨ
k
+
1
. Now apply Lemma
6.28
.
Let
ʔ
:
=
k
=
0
ʔ
k
.
By (iii) and (iv) above,
we obtain a weak
˄
move
=
k
=
0
(
ʔ
k
|
A
t
), by (v) and Definition
6.2
we have
ʔ
0
⃒
ʔ
. Since
ʔ
|
A
t
−ₒ
p
k
=
1
ʓ
k
˄
ʔ
|
A
t
Note that here it does not matter if
ʔ
.
=
ʵ
.
Since
ʓ
k
ʵ
, it follows from Theorem
6.5
(ii) that
ʓ
k
≤
ʓ
k
≤
ʨ
k
and
ʨ
k
⃒
⃒
ʵ
.
Hence by using Theorem
6.5
(i), we obtain that
k
=
1
ʓ
k
⃒
ʵ
.
We are now ready to prove the main result of this section, namely that
FS
is
preserved by the parallel operator.
FS
ʔ then ʘ
|
A
Φ
FS
ʔ
|
A
Φ.
Proposition 6.11
In a finitary pLTS, if ʘ
Proof
We first construct the following relation
C
R
:
={
(
s
|
A
t
,
ʘ
|
A
t
)
|
s
FS
ʘ
}
FS
. As in the proof of Theorem 5.1, one can check that
each strong transition from
s
and check that
R
ↆ
|
A
t
, and the
matching of failures can also be established. So we concentrate on the requirement
involving divergence.
Suppose
s
|
A
t
can be matched by a transition from
ʘ
FS
ʘ
and
s
|
A
t
⃒
ʵ
. We need to find some
ʓ
,
ʨ
such that
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