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0
1/9
8/9
0
k=3
˄
˄
1/16
k=4
s
3/4
k=2
15/16
˄
1/4
˄
k=5
0
24/25
1/25
0
Fig. 6.4 Infinitely branching flower. There are two states s and 0 . To diverge from s with probability
1 1 /k , start at “petal” k and take successive ˄ -loops anti-clockwise from there. Yet, although
divergence with arbitrarily high probability is present, complete probability-1 divergence is nowhere
possible. Either infinite states or infinite branching is necessary for this anomaly
Example 6.14 (Revisiting Example 6.5 ) The pLTS in Example 6.5 is an infinite
state system over states s k for all k
2, where the probability of convergence is 1 /k
from any state s k , thus a situation where distillation of divergence fails because all
the states partially diverge, yet there is no single state that wholly diverges.
Example 6.15 Consider the finite state but infinitely branching pLTS described in
Fig. 6.4 ; this consists of two states s and 0 together with a k -indexed set of transitions
˄
−ₒ k ([[ 0 ]] 1 /k 2
s
s )
for k
2,
(6.20)
This pLTS is obtained from the infinite state pLTS described in Example 6.5 by
identifying all of the states s i and replacing the state a. 0 with 0 .
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