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ʘ if and only if ʘ can
Lemma 6.5
For subdistributions over a finite set S, ʔ R
be written in the form s ʔ ʔ ( s )
· ʘ s where each ʘ s R
( s ) .
= s ʔ
ʘ ,it
Proof
Suppose ʘ
ʔ ( s )
·
ʘ s with ʘ s R
( s ). To show that ʔ
R
ʘ s for each s
suffices to prove that s
R
ʔ
,as
R
is linear. Since ʘ s R
( s ),
we can rewrite ʘ s as ʘ s = i I p i ·
ʘ i s where ʘ i s R
( s ) for some finite index set
= i I p i ·
ʘ s .
I . The fact that s
s and s
R
ʘ i s yields that s
R
ʘ . By Lemma 6.1 we have that
Conversely, suppose ʔ
R
ʔ
=
p i ·
s i
s i R
ʘ i
ʘ
=
p i ·
ʘ i .
(6.2)
i I
i I
= i I s p i . Hence, we
For each s
ʔ
, let I s ={
i
I
|
s i =
s
}
. Note that ʔ ( s )
can rewrite ʘ as follows:
= s ʔ i I s p i ·
ʘ
ʘ i
= s ʔ
( i I s
p i
ʔ ( s ) ·
ʔ ( s )
·
ʘ i )
Since the subdistribution i I s
p i
ʔ ( s ) ·
ʘ i is a convex combination of
{
ʘ i |
i
I s }
,it
must be in
R
( s ) due to ( 6.2 ), and the result follows.
Theorem 6.4 (Infinite Linearity) Suppose
R
is a relation over S
× D sub ( S ) , where S
is finite and i 0 p i =
ʘ i implies ( i 0 p i ·
( i 0 p i ·
1 . Then ʔ i R
ʔ i )
R
ʘ i ) .
Suppose i 0 p i =
Proof
1 and ʔ i
R
ʘ i for each i
0. Let ʔ , ʘ denote
i 0 p i ·
ʔ i and i 0 p i ·
ʘ . By Lemma 6.5
ʘ i , respectively. We have to show ʔ
R
it is sufficient to show
ʘ =
ʔ ( s )
· ʓ s ,
(6.3)
s ʔ
where ʓ s R
.
By the same lemma we know that for each i
( s ) for each s
ʔ
ʘ i ,
0, since ʔ i R
ʘ i =
ʔ i ( s )
·
ʘ i s with ʘ i s R
( s ) .
(6.4)
s ʔ i
Therefore,
= i 0 p i ·
( s ʔ i ʔ i ( s )
·
ʘ
ʘ i s )
= s ʔ i 0 ( p i ·
ʘ i s
Let w i denote p i · ʔ i ( s ) and note that ʔ ( s ) is the infinite sum i 0 w i . Therefore,
we can continue:
ʔ i ( s ))
·
= s ʔ i 0 w i ·
ʘ
ʘ i s
= s ʔ ʔ ( s )
( i 0
w i
·
ʔ ( s ) · ʘ i s ) .
 
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