Civil Engineering Reference
In-Depth Information
Figure 11.10 CPM network solution to example 11.2
and
σ E = 3
.
14 = 1
.
77 days
To find the duration with a minimum level of confidence of 95%, find the Z
values associated with the probability of 0.95. From the table, this Z value is
1.645 and
T S E Z + T E = 1
.
771
.
645 + 55
.
50 = 58
.
41 days
Applying the same calculations to path ABDG, we find
T E = 5
.
00 + 12
.
00 + 17
.
33 + 22
.
00 = 56
.
33days
V E = 0
.
11 + 0
.
44 + 1
.
78 + 21
.
78 = 24
.
11
σ E = 24
.
11 = 4
.
91days
and
T S E Z + T E = 4
.
911
.
645 + 56
.
33 = 64
.
41days
Applying the same calculations again to path ABEHI, we find
T E = 5 . 00 + 12 . 00 + 16 . 67 + 12 . 27 + 9 . 00 = 54 . 83days
V E = 0
.
11 + 0
.
44 + 11
.
11 + 0
.
69 + 0
.
11 = 12
.
47
σ E = 12
.
47 = 3
.
53days
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