Precedence Networks - Construction Project Scheduling and Control - page 114

Activity H had 3 days of total float in the “interruptible activities” solution, and
now the float has added 2 days to become 5.
Note also that a relationship between two critical activities is not neces-
sarily critical. For example, the FF relationship between activities E and I is not
driving and, thus, is not critical.

Figure 5.27 Solution for example 5.2 with interruptible activities

3, 7

3

C
4 30, 39

0, 10
A
10

3, 7

H
9

‒ 1

35, 44

0, 10

2, 30 44, 56

8

2

D
28

I
12

PS

24, 38

0, 12

E
14

2, 30

44, 56

B
12

24, 38

12, 22

24, 44

0, 12

F
10

G
20

14, 24

24, 44

Figure 5.28 Solution for example 5.2 with contiguous activities