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p 2 [ µ 1 3
β 2 )
+ 2 β 2 µ 3 ]
p 1 [ µ 2 3
+ 2 β 2 µ 3 ]
+ 2 β 2 p 3 1 µ 2 )
β 2 )
T 22 =
(11.A.8)
µ 2 )(β 2
α 3 )
1
+
p 1
p 3
T 23 =
(11.A.9)
µ 1
µ 2
α 1 q 1 D 2 α 2 q 2 D 1 +
α 3 (D 2 D 1 )
β 2 q 3
T 24 =−
(11.A.10)
p 1 µ 2
p 3
ωβ
N(β 2
µ 3
p 2 µ 1
µ 3
T 25 =−
µ 1 +
µ 2
(11.A.11)
α 3 )
+
µ 2
µ 1
α 1 q 1 (C 2 + 2 2 )
C 2 )
q 3 β 2
α 3 (C 1
α 2 q 2 (C 1 + 2 2 )
T 26 =
(11.A.12)
2 N(α 1 µ 1 q 1 D 2 α 2 µ 2 q 2 D 1 )
α 3 (C 1 D 2 C 2 D 1 )
µ 3 q 3
T 31 =
(11.A.13)
µ 1 p 1 [ µ 2 3
β 2 )
2 β 2 µ 3 ]
µ 2 p 2 [ µ 1 3
2 β 2 µ 3 ]
+ 2 β 2 µ 3 p 3 1
β 2 )
+
+
+
µ 2 )
T 32 =
(11.A.14)
µ 2 )(α 3 +
1
β 2 )
µ 1 p 1
µ 2 p 2
µ 1 µ 2
T 33 =
(11.A.15)
D 2 )
β 2 µ 3 q 3
α 3
T 34 =
α 1 µ 1 q 1 D 2 +
α 2 µ 2 q 2 D 1 +
(D 1
(11.A.16)
p 1 µ 1 µ 2
p 3 µ 3
βω
N(α 3 +
µ 3
p 2 µ 2 µ 1
µ 3
T 35
=
µ 1 +
µ 2
(11.A.17)
β 2 )
µ 2
µ 1
µ 1 α 1 q 1 (C 2
C 2 )
β 2
α 3 µ 3 q 3 (C 1
2 2 )
2 2 )
T 36
=
+
µ 2 α 2 q 2 (C 1
+
(11.A.18)
2
ω [ C 1 p 1 D 2
T 41 =
C 2 p 2 D 1
p 3 (C 1 D 2
C 2 D 1 ) ]
(11.A.19)
C 1 q 1 α 2 [ µ 2 3 β 2 ) + 2 β 2 µ 3 ] C 2 q 2 α 1 [ µ 1 3 β 2 ) + 2 β 2 µ 3 ]
4 3 β 2 α 1 α 2 1
µ 2 )q 3
T 42 =− j
+ α 3 )(µ 1 µ 2 )
α 1 α 2 ω(β 2
(11.A.20)
T 43 = j α 2 C 1 q 1
α 1 C 2 q 2
(11.A.21)
ωα 1 α 2 1
µ 2 )
p 2 C 2 D 1 2 2 p 3 (D 2
T 44 =
p 1 C 1 D 2 +
D 1 )
(11.A.22)
C 1 q 1
1
µ 2 2 q 3 α 3
µ 2
µ 3
C 2 q 2
2
µ 1
µ 3
T 45 =
µ 1 +
(11.A.23)
+ α 3
µ 2
µ 1
β 2
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