Global Positioning System Reference
In-Depth Information
From the triangle OPC and the law of sine, one can write
sin D
OC
sin
L)
=
( 2 . 36 )
r
From Equation (2.35),
e e OE
e e r 0 cos L co
OC
=
=
( 2 . 37 )
but
L co =
L
D 0
( 2 . 38 )
Therefore,
e e r 0 cos (L
e e r 0 ( cos L cos D 0 + sin L sin D 0 )
OC
=
D 0 )
=
( 2 . 39 )
From Equation (2.23), the ellipticity e p of the earth is
a e b e
a e
e p
=
( 2 . 40 )
The eccentricity and the ellipticity can be related as
a e b e
a e
(a e b e )
a e
(a e + b e )
a e
e p ( 2 a e a e + b e )
a e
e e =
e p )
( 2 . 41 )
Substituting Equations (2.39) and (2.41) into Equation (2.36), the result is
=
=
=
e p ( 2
1
2 sin 2 L cos D 0 +
sin 2 L sin D 0
2 e p 1
e p
2
r 0
r 0 +
sin D
=
( 2 . 42 )
h
In the above equation the relation r
h is used. Since D and D 0 are both
very small angles, the above equation can be written as
=
r 0 +
1
2 sin 2 L
D 0 sin 2 L
2 e p 1
e p
2
r 0
r 0 +
D
=
+
( 2 . 43 )
h
The relations
sin D
D ; s p sin D 0
D 0 ; s p cos D 0 1
( 2 . 44 )
are used in obtaining the results of Equation (2.43). If the height h
= 0, then
from Figure 2.7 D
D 0 . Using this relation Equation (2.43) can be written as
D 0 1 2 e p 1
=
2 sin 2 L
e p 1
2 sin 2 L or
e p
e p
=
D 0 =
e p sin 2 L
+
1
(2.45)
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