Global Positioning System Reference
In-Depth Information
From the triangle
OPC
and the law of sine, one can write
sin
D
OC
sin
(π
−
L)
=
(
2
.
36
)
r
From Equation (2.35),
e
e
OE
e
e
r
0
cos
L
co
OC
=
=
(
2
.
37
)
but
L
co
=
−
L
D
0
(
2
.
38
)
Therefore,
e
e
r
0
cos
(L
e
e
r
0
(
cos
L
cos
D
0
+
sin
L
sin
D
0
)
OC
=
−
D
0
)
=
(
2
.
39
)
From Equation (2.23), the ellipticity
e
p
of the earth is
a
e
−
b
e
a
e
e
p
=
(
2
.
40
)
The eccentricity and the ellipticity can be related as
a
e
−
b
e
a
e
(a
e
−
b
e
)
a
e
(a
e
+
b
e
)
a
e
e
p
(
2
a
e
−
a
e
+
b
e
)
a
e
e
e
=
e
p
)
(
2
.
41
)
Substituting Equations (2.39) and (2.41) into Equation (2.36), the result is
=
=
=
e
p
(
2
−
1
2
sin 2
L
cos
D
0
+
sin
2
L
sin
D
0
2
e
p
1
e
p
2
r
0
r
0
+
sin
D
=
−
(
2
.
42
)
h
In the above equation the relation
r
h
is used. Since
D
and
D
0
are both
very small angles, the above equation can be written as
=
r
0
+
1
2
sin 2
L
D
0
sin
2
L
2
e
p
1
e
p
2
r
0
r
0
+
D
=
−
+
(
2
.
43
)
h
The relations
sin
D
≈
D
;
s
p
sin
D
0
≈
D
0
;
s
p
cos
D
0
≈
1
(
2
.
44
)
are used in obtaining the results of Equation (2.43). If the height
h
=
0, then
from Figure 2.7
D
D
0
. Using this relation Equation (2.43) can be written as
D
0
1
−
2
e
p
1
−
=
2
sin
2
L
e
p
1
−
2
sin 2
L
or
e
p
e
p
=
D
0
=
e
p
sin 2
L
+
1
(2.45)
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