Chemistry Reference
In-Depth Information
is given by
2 k 2
2 k 2
m 2
2
|
i
·
p nn |
+
2 m +
E n k =
E n 0
(4.4a)
E n 0
E n 0
n =
n
where i is a unit vector pointing along the direction i , and p nn is the
momentum matrix element linking the n th and n th basis state of H 0 (see
Appendix E). From the definition of m above, we can then estimate the
effective mass along the direction i in the n th band, m i ,as
m 2
n =
2
1
m i =
1
m +
2
|
i
·
p nn |
(4.4b)
E n 0
E n 0
n
For real semiconductors, we should take account of the spin-orbit interac-
tion and also of band degeneracies, neither of which were included in the
derivation of eq. (4.4). The practical application of the k
·
p model, therefore,
looks rather complicated. However, two main reasons help to ensure its
usefulness (Kane 1966; Bastard 1988):
1 Inmost cases, we only have to deal with a very small number of bands,
whichare close to eachother in energy, and can ignore higher and lower
bands, where the denominator in the summation terms of eq. (4.4) is
large.
2 When we restrict the number of bands in eq. (4.4), and then start
to fit experimental data, such as measured effective masses, m ,
and measured energy gaps E n 0
E n 0 it is found that the momen-
tum matrix elements p nn are remarkably constant between different
semiconductors, with p nn
identically zero for many pairs of bands n
and n .
We can consider a very simple (but not totally unrealistic) model of
a direct-gap semiconductor, with zero spin-orbit splitting. The conduc-
tion band consists of a single s-like anti-bonding state at k
=
0, while the
top of the valence band has pure p-like symmetry, so is threefold degener-
ate. We choose the three p states to point along the three crystal axes, and
label them p x ,p y and p z , respectively.
It can be shown from symmetry considerations that the matrix elements
p ij linking any pair of the p states are identically zero, while themomentum
matrix element linking s with each p level points along the direction of that
p state, so that p sx =
P i say, with p sy =
P j and p sz =
P k , where i , j , and k
are unit vectors along the three crystal axes.
If we assume that the wavevector k points along the x -direction, then the
matrix elements k
·
p nn corresponding to k
·
p sy and k
·
p sz are identically
 
Search WWH ::




Custom Search