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V 0
b
L
Position
Figure C.2 Infinite square well of width L , with a barrier of height V 0 and width b
added in its centre.
to estimate the energy of that state, W ( 1 )
k
,as
d V
ψ ( 0 )
k
ψ ( 0 )
k
(
r
)
H
(
r
)
W ( 1 )
k
=
(C.6)
d V
ψ ( 0 )
k
( 0 )
k
(
r
(
r
)
H
where the denominator in eq. (C.6) is equal to 1. Replacing H by H 0
+
and splitting the integral in eq. (C.6) into two parts gives
W ( 1 )
k
ψ ( 0 )
k
ψ ( 0 )
k
ψ ( 0 )
k
H ψ ( 0 )
k
=
d V
(
r
)
H 0
(
r
) +
d V
(
r
)
(
r
)
E ( 0 )
k
ψ ( 0 )
k
H ψ ( 0 )
k
=
+
d V
(
r
)
(
r
)
(C.7)
The energy levels E ( 0 k of the Hamiltonian H 0 thus provide the zeroth-
order guess for the energy levels of the full Hamiltonian H , while E ( 1 )
k
=
d V
ψ ( 0 )
k
H ψ ( 0 )
k
(
)
(
)
r
r
gives the first order correction to the estimated
energy.
C.2.1 Example: double square well with infinite outer barriers
To illustrate the application of first order perturbation theory, we consider
an infinite squarewell in the region 0
<
x
<
L , towhich is added a potential
barrier of height V 0 and width b between L
/
2
b
/
2 and L
/
2
+
b
/
2 (fig. C.2).
The energy levels E ( 0 n and wavefunctions
ψ ( 0 )
(
x
)
of the unperturbed well
n
are given by (eq. (1.11))
h 2 n 2
8 mL 2
E ( 0 )
=
(C.8a)
n
 
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