Chemistry Reference
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number of terms. Here we need only note that allowed solutions will only
exist if the coefficient of each power of z in the polynomial is identically
zero when substituted into eq. (B.8).
If the leading term of the polynomial P is z n , substitution into eq. (B.8b)
shows that the leading power in the differential equation is z n + 2 , with
coefficient n
2 . Thismust vanish, so
(
n
1
) λ
λ =
n
(
n
1
)
. It is conventional
to put n
=
l
+
1, and so to write
λ =
(
+
)
l
l
1
(B.9)
Further detailed analysis shows that allowed solutions can only exist when
l
m 2 , which requires
(
l
+
1
)>
l
m
l
(B.10)
so that there are 2 l
1 allowed values of m for each value of l .
We now substitute eq. (B.9) for
+
λ
back into eq. (B.4) to derive the radial
Schrödinger equation
R
r 2 d R
d r
2
2
1
d
d r
l
(
l
+
1
)
r 2
+
+
V
(
r
)
(
r
) =
ER
(
r
)
(B.11)
2 m
2 m
r 2
The l -dependent termmaybewrittenas Q 2
2 mr 2 , and is the quantumcoun-
terpart of the classical 'centrifugal' potential barrier Q 2
/
2 mr 2 encountered
for example in the Kepler problem of planetary orbits, where Q
/
mr 2
is
the angular momentum of the orbiting particle. We have thus shown that
the angular momentum is quantised in a spherically symmetric potential,
with the magnitude squared of the angular momentum Q 2
=
ω
2 l
,
where l is an integer. Further analysis reveals that if we quantise along
a particular direction (e.g. along the z -axis) then the angular momen-
tum component along that axis is also quantised, with the component Q z
projected onto that axis equal to
=
(
l
+
1
)
Q z
=
m ,
|
m
|≤
l
(B.12)
We note that eq. (B.11) depends on the total angular momentum through
the term containing l
, but does not depend on m , the angular momen-
tum component along the quantisation axis. This is to be expected. The
energy should not depend on the orientation of the z -axis in a spherically
symmetric potential.
Equation (B.11) can be solved for the hydrogen atom using standard
mathematical techniques, again described in many quantum mechanics
texts. To avoid having to work with a large number of constants ( e , m ,
(
l
+
1
)
,
etc.) we introduce a change of variables
2 me 2
=
8 mE
2
ρ = α
r ;
α
;
β =
(B.13)
2
2
4
πε
α
0
 
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