Information Technology Reference
In-Depth Information
g
more information is needed, but in the absence of it, we
can decide to take the linear models f
To determine f and
x
32
5
43
x
(
) =
g(
) =
x
, and
x
, with which
2
3
5 ,
1
2 .
μ A g e ( p ) (
) =
μ A g e ( p ) (
) =
35
42
As it will be seen later on, 0.6 is the possibility that A
g
e
(
p
) =
35, and 0.5 that
of A
g
e
(
p
) =
42. Hence, it seems a little bit more possible that it be ' A
g
e
(
p
) =
42'
than ' A
g
e
(
p
) =
35'.
Example 2.2.49
Knowing that Height(John)
=
175 cm, and Height(Peter)
=
180 cm,
consider the two statements:
p
=
It is false that John is not very tall or is more or less short
q
=
It is false that Peter is not very tall or is more or less short.
which is more true?
Solution . Both statements can be written by
Is false that x is P ,
with P
=
'(not very tall) or (more or less short)'.
Hence
v er y t all (
2
μ P (
x
) =
S
x
), μ not short (
x
)) =
S
(
N
tall (
x
)
),
μ tall (
A
(
x
)) ),
with a continuous t-conorm S , a strong negation N ,andasymmetry A on X , provided
x varies in a scale of heights.
What should be compared are the two values N
P (
))
P (
))
175
and N
180
, and
μ tall . Let us take
for that it is needed to know
0
,
if x
∈[
0
,
150
]
μ tall (
x
) =
strictly non decreasing
,
if x
∈[
150
,
190
]
1
,
if x
∈[
190
,
210
]
with, perhaps,
μ tall (
x
) =
0
.
025 x
3
.
75
,
x
∈[
150
,
190
]
, if we need to have numbers.
Hence, with A
(
x
) =
210
x
,
it is A
(
175
) =
210
175
=
35
,
and
μ tall (
35
) =
0,
as well as A
(
180
) =
220
180
=
30, and
μ tall (
30
) =
0, because of that
2
μ P (
175
) =
S
(
N
tall (
175
)),
0
) =
N
tall (
175
)
)
2
μ P (
180
) =
S
(
N
tall (
180
)),
0
) =
N
tall (
180
)
)
.
Since
μ tall is strictly non-decreasing between 150 and 190, it is
μ tall (
175
)<
2
2
μ tall (
180
)
, and N
tall (
180
)
)<
N
tall (
175
)
)
. Finally,
2
2
2
2
N
(
N
tall (
175
)
)) <
N
(
N
tall (
180
)
))
,or
μ tall (
175
)
< μ tall (
180
)
,
and q is strictly more true than p .
 
Search WWH ::




Custom Search