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Sixth Step: Several Rules with Numerical Input
The problem is now
By using the CRI, R 1 with the input “ x is P ” gives an output “ y is Q 1 ”, with
μ Q 1 its membership function and R 2 with the input “ x is P ”gives“ y is Q 2 ” with
μ Q 2 its membership function. The total output, “ y is Q ”, corresponds to the idea
( y is Q 1 ) or ( y is Q 2 ), and translating this ' or ' by means of the lowest t-conorm its
value can be obtained by
.
For example, the Mandani's method consist in taking J
μ Q (
y
) =
Max
Q 1 (
y
), μ Q 2 (
y
))
(
a
,
b
) =
Min
(
a
,
b
)
and
the Larsen's method, in taking J
(
a
,
b
) =
a
·
b . Let us consider in X
=[
0
,
10
]
,
Y
=[
0
,
1
]
the problem:
R 1 :
If x is close - to 4
,
then y is big
R 2 :
If x is small
,
then y is small
x
=
3
.
5
μ Q using both methods by supposing “ close - to 4” as in the former
and let us find
x
10
example,
μ big (
y
) =
y ,
μ small (
x
) =
1
, and
μ small (
y
) =
1
y .
The outputs Q 1 , Q 2 are:
μ
μ
IF
THEN
close-to 4
big
1
1
μ
Q
1
R1:
0.5
0
1
4
5
0
0.5
3
10
μ
IF
THEN
μ
small
small
1
1
μ
0.65
2
Q
R2:
0
1
0
0.35
3.5
10
 
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