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a +
=
(
,
) =
(
(
),
)
[
,
]
S -implications: a
b
b and J
a
b
S
N
a
b
for all a , b in
0
1
,
with some strong negation function N and some continuous t-conorm S .
a +
R -implications: a
b
=
b and J
(
a
,
b
) =
Sup
{
z
∈[
0
,
1
];
T
(
z
,
a
)
b
}=
J T (
a
,
b
))
for all a , b in
[
0
,
1
]
and some continuous t-norm T .
a +
Q -implications: a
b
=
a
·
b and J belongs to the family J
(
a
,
b
) =
S
(
N
(
a
),
T
(
a
,
b
)
.
ML -implications: a
b
=
a
·
b and J is in the family of functions J
(
a
,
b
) =
T
(
a
,
b
)
.
In fuzzy control mostly ML-implications are considered. Since T is a continu-
ous t-norm, it is T
˕ = ˕ 1
=
Min ,or T
=
Prod
Prod
× ˕)
,or
˕ = ˕ 1
T
=
W
W
× ˕)
, with
˕
an order-automorphism of the unit
interval (
.Of
course, T can be also an ordinal-sum, but these t-norms have never been considered
in fuzzy logic. Hence, a ML -implication belongs to the types: J M (
[
0
,
1
] ,
), Prod
(
x
,
y
) =
x
·
y and W
(
x
,
y
) =
Max
(
0
,
x
+
y
1
)
a
,
b
) =
Min
(
a
,
b
)
,
J L (
a
,
b
) =
Prod ˕ (
a
,
b
)
and J W (
a
,
b
) =
W ˕ (
a
,
b
)
. Only in the third type we can
have J
(
a
,
b
) =
0 with a
=
0 and b
=
0, since it is W ˕ (
a
,
b
) =
0 whenever
˕(
a
) + ˕(
b
)
1, and as in fuzzy control it is desirable not only that a
=
0 implies
J
(
a
,
b
) =
0 but also that a
=
0 and b
=
0imply J
(
a
,
b
) =
0, the third type is rarely
used and only J M (
b
(Larsen implication) are almost always considered. Notice that for all S , and Q
implication functions it is: J
a
,
b
) =
Min
(
a
,
b
)
(Mamdani implication) and J L (
a
,
b
) =
a
·
(
0
,
b
) =
1.
Second Step: Modus Ponens
Rules are used in our problem to infer
μ Q , and this inference requires that when the
states of the input variables x 1 ,...,
x n are exactly those appearing in the antecedent
part of one of the m rules, say rule number i , then
μ Q should be the consequent
μ Q i
of this rule. That is, each rule should satisfy the meta-rule of Modus Ponens:
This meta-rule is satisfied when there is a continuous t-norm T 1 such that
T 1 P (
x
),
R
P , μ Q )(
x
,
y
)) μ Q (
y
),
for all x
X , y
Y . When R
P , μ Q )(
x
,
y
) =
J
P (
x
), μ Q (
y
))
,thelast
inequation is
T 1 P (
x
),
J
P (
x
), μ Q (
y
)) μ Q (
y
),
for all x
Y .
Hence, for each type of implication function J we need to know which T 1 allows
the verification of the Modus Ponens inequality:
X , y
T 1 (
a
,
J
(
a
,
b
))
b
,
for all a
,
b
∈[
0
,
1
] .
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