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then,
2 A
=
20
(
1
x 0 )
x 0 +
20
(
1
x 0 )
x 0 + (
1
2 x 0 )(
10
20 x 0 ),
and
20 x 0 =
A
=
20 x 0 (
1
x 0 ) +
5
20 x 0 +
5
.
Hence,
y 0
50
y
10 dy
10 x 0 +
100 x 0 ,
=
2
.
5
y 0 =
10 x 0
and
50
(
) =
100 x 2
,
/
.
CRI
x
if x
1
2
41
For example, CRI
(
0
.
5
) =
0
.
5, and CRI
(
0
.
3
) =
=
6
.
4, as it was shown. It
is also CRI
(
0
.
1
) =
7.
) = 20
100 x 2
Last formula, CRI
(
x
100 x 2 , gives real values provided 20
0, or x 2
5, that implies x 2
1
/
5. Since, it is x
1
/
1
/
4
1
/
2, and it follows
that the formula is useful for all x
∈[
0
,
1
]
such that x
1
/
2.
2. For any input x 0
1
/
2, the graphic is
and the area below
μ Q
is
x 0 + (
10 x 0
10
(
1
x 0 ))(
x 0
1
+
x 0 )
A
=
10 x 0 (
1
x 0 ) + (
10
10 x 0 )
2
=
20 x 0 (
1
x 0 ) + (
10 x 0
5
)(
2 x 0
1
) =
5
.
Hence, A
/
2
=
2
.
5, and
y 0
y 0
y
10 dy
2
2
10
(
1
x 0 )
+
=
2
.
5, or 100
(
1
x 0 )
+
ydy
=
2
.
5
,
10
(
1
x 0
)
10
(
1
x 0
)
 
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