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For 5 :
M,s ¬Kφ ₒ K¬Kφ
⃒⃐ M ,s 0 implies M,s 0 K¬Kφ
⃒⃐ M ,s φ implies M,s ¬Kφ
⃒⃐ M ,s φ implies M,s
⃒⃐ M ,s φ implies M,s φ
For 4 :
M
,s
KKˆ
⃒⃐ M
,s
0 implies
M
,s
0 KKˆ
⃒⃐ M
,s
ˆ implies
M
,s
ˆ
Based on Lemma 1, we also have the following results: 2
M
,s and any EAL formula ˆ the follow-
Proposition 1. Fo r any pointed hyper model
ing hold:
1.
M
,s
ˆ
∧¬
ˆ ,i.e.,
is consistent.
2.
M
,s
ˆ
∨¬
ˆ , i.e.,
is complete.
3.
is consistent andcomplete.
Proof. Lemma 1 says that for any
M
,s any formula EAL ˆ :
M
,s
ˆ implies
M
ˆ .
For (1): Suppose
,s
M
,s
¬
ˆ then
M
,s
ˆ therefore
M
,s
ˆ .Thus
M
,s
ˆ
∧¬
ˆ .
For (2): (
M
,s
ˆ or
M
,s
¬
ˆ )
⃒⃐
(
M
,s
ˆ or
M
,s
ˆ )
⃒⃐
(
M
,s
ˆ implies
M
,s
ˆ ). (3) is trivial by definition.
One way to interpret the above results is that the knowledge is consistent, and at least
one of ˆ and
¬
ˆ is considered possible by the agent. On the other hand,
is not
complete and
is not consistent, which can be demonstrated by the following simple
example in which the agent has no information ( a
a
are empty):
and
t
s
a
According to the semantics,
M
,s
a
∧¬
a
,andequivalently we have
M
,s
¬
a
and
M
,s
a
. The “inconsistency” of
does not cause the inconsis-
tency of
due to the semantics of the negation. Clearly,
a
∨ ¬
a
is valid but
K (
a
∨¬
a
) is not valid in the above model, thus:
Proposition 2. Therule of necessitation (
ˆ infers
)isnot valid.
On the other hand, our K operator is more constructive than the standard epistemic
operator, demonstrated by the fact that K operator actually distributes over both
and
.Inour setting, K ( ˆ
ˈ ) should be read as 'the agent knows whether ˆ or ˈ '.Cor-
respondingly, K ( ˆ
ˈ ) should be read as ' the agent considers both ˆ and ˈ possible'.
Proposition 3. The following are valid:
DIST
: K ( ˆ
ˈ )
DIST
: K ( ˆ
ˈ )
Since there is no uncertainty of basic propositions in the hyper models, the following
holds:
2
The use of the words consistent and complete are due to the convention in the abstraction
literature c.f. e.g., [3].
 
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