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Proof. All of (i), (ii) and (iii) are proved by simultaneousinduction on len(
)
len( L ),
˕
×
γ
where
is a formula
or
. We show the cases (i) and (ii) for
. In Appendix A.4, the
˕
ˈ
γ
reader can find arguments for case (iii) fully and the cases for
of the form p ,[
]
.
Let
˕ ≡ γ
. For (i), assume (
˃
: ˁ 1 ; ··· ; ˁ n γ
)
∈ ʘ
; we show that
γ ( M ʘ ) ∩ˁ 1 ; ··· ; ∩ˁ n
(
˄ ʘ ) ∩ˁ 1 ; ··· ; ∩ˁ n (
˃
)or,equivalently,
[
ˁ 1 ]
···
[
ˁ n ]
γ M ʘ ∈˄ ʘ (
˃
). It su
ces to show both
- (
˃
: L γ
)
∈ʘ
,
W ʘ |
˃ : L ×
∈ʘ
˃ : L γ
∈ʘ}ↆ
ˁ 1 ]
···
ˁ n ]
γ M ʘ .
-
(
)
or (
)
[
[
The first is the assumption; the second holds by induction hypothesis. For (ii), assume
(
˄ ʘ ) ∩ˁ 1 ; ··· ; ∩ˁ n (
˃
: L ¬γ
)
∈ ʘ
; we show that
γ ( M ʘ ) ∩ˁ 1 ; ··· ; ∩ˁ n
(
˃
)or,equivalently,
γ M ʘ ˄ ʘ (
and L ,
[
ˁ 1 ]
···
[
ˁ n ]
˃
), i.e., for all
˕
W ʘ |
˃ : L ×
˃ : L ˕
(
˃
: L ˕
)
∈ʘ
implies
(
)
∈ʘ
or (
)
∈ʘ}
[
ˁ 1 ]
···
[
ˁ n ]
γ M ʘ
and L such that (
Thus, take any
˕
˃
: L ˕
)
∈ ʘ
.Bythesaturatedness of
ʘ
and rule
) we obtain, for some fresh
(
˃ ne w , either
(
˃ ne w : L ˕
)
,
(
˃ ne w : L ¬γ
)
∈ʘ
or (
˃ ne w : L ×
)
,
(
˃ ne w : L ¬γ
)
∈ʘ
.
˃ ne w : L ¬γ
∈ʘ
γ
In either case, it follows from (
)
and induction hypothesis that
is false
˃ ne w in (
M ʘ ) ∩ˁ 1 ; ··· ; ∩ˁ n , which is equivalent to
M ʘ ne w |=
ˁ 1 ]
···
ˁ n ]
γ
at
[
[
. This finishes
W ʘ |
˃ : L ×
∈ʘ
˃ : L ˕
∈ʘ}
ˁ 1 ]
···
ˁ n ]
γ M ʘ .
establishing our goal;
(
)
or (
)
[
[
Theorem 5. Given any formula
˕
,ifthere is an open saturated tableau for (
˃ initial : ˕
) ,
then
˕
is satisfiable in theclass of all MNMs for intersection semantics.
Proof. By assumption, there is an open saturated branch
ʘ
containing (
˃ initial : ˕
).
M ʘ initial |= ˕
By Lemma 5,
, which implies the satisfiability of
˕
in the class of all
MNM s for intersection semantics.
Now, let us move to the
-semantics.
M ʘ =
( W ʘ ʘ ,
V ʘ )
Lemma 6. Givenanopen saturated branch
ʘ
,definethe model
W ʘ ,X
∈˄ ʘ (
asin Lemma 5 except that, for every
˃∈
˃
) i
ff
W ʘ |
˃ : L ˕
(
˃
: L ˕
)
∈ʘ
and
(
)
∈ʘ}ↆ
X r me
˕
andL.
1 ;
···
ˁ n and all formulas
˕
Then,forall lists L
;
,
M ʘ ) ↆˁ 1 ; ··· ; ↆˁ n
(i) (
˃
: L ˕
)
∈ʘ
implies (
,˃|=˕
M ʘ ) ↆˁ 1 ; ··· ; ↆˁ n
(ii) (
˃
: L ¬˕
)
∈ʘ
implies (
,˃|=˕
M ʘ ) ↆˁ 1 ; ··· ; ↆˁ n .
(iii) (
˃
: L ×
)
∈ʘ
implies
˃
is not in thedomain of (
Proof. All of (i), (ii) and (iii) are proved by simultaneousinduction on len(
)
+
len( L ),
˕
×
˕
γ
where
is a formula
or
. We show cases (i) and (ii) for
of the form
.
˃
: L γ
∈ʘ
M ʘ ) ↆˁ 1 ; ··· ; ↆˁ n
,˃|=γ
γ ( M ʘ ) ↆˁ 1 ; ··· ; ↆˁ n
For (i), assume (
)
; we show that (
,i.e.,
˄ ʘ ) ↆˁ 1 ; ··· ; ↆˁ n (
˃
ˁ 1 ···ˁ n γ M ∈˄ ʘ (
˃
(
)or,equivalently,
). It su
ces to show
W ʘ |
˃ : L γ
(
˃
: L γ
)
∈ʘ
and
(
)
∈ʘ}ↆˁ 1 ···ˁ n γ M ʘ
 
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