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Q ult
q ult B
L
(208 kN/m 2 ) (1.4 m) (1.4 m)
408 kN
Q ult
408 kN
___
_______
FS
Q
500 kN
0.82
8.14
Solution using Eq. (8.7):
Q
P
15,000 kips
for mat foundation
e 5 ft
(for middle third of mat, e cannot exceed 16.7 ft, so e is
within middle third of mat)
Converting Q to a load per unit length of the mat gives
Q 15,000 kips
__________
100 ft 150 kips/ft 150,000 lb/ft
q Q ( B 6 e )
150,000 [100 6 (5)]
__________
___________________
B 2
100 2
1950 lb/ft 2
Since 1950 2500 lb/ft 2 , design is acceptable.
Solution using Fig. 8.9:
Q P 15,000 kips 15,000,000 lb
for mat foundation
e 5 ft
B B 2 e 100 2 (5) 90 ft
L L 100 ft
(moment only in B direction of mat)
B L 15,000,000
Q
____
__________
q
100 (90) 1670 lb/ft 2
Since 1670 2500 lb/ft 2 , design is acceptable.
8.15
Strip footing:
q all 24 kPa 24 kN/m 2
Using B
1.5 m yields
(24 kN/m 2 ) (1.5 m)
Q all
36 kN/m
Spread footing:
q all 32 kPa 32 kN/m 2
Using B
L
2.5 m gives
Q all
q all BL
(32 kN/m 2 ) (2.5 m) (2.5 m)
200 kN
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