type Error or RuntimeException, or any of their subclasses. All other exceptions that a method
can throw must be declared in the throws clause. If they are not, a compile-time error will result.
This is the general form of a method declaration that includes a throws clause:
type method-name(parameter-list) throws exception-list
{
// body of method
}
Here, exception-list is a comma-separated list of the exceptions that a method can throw.
Following is an example of an incorrect program that tries to throw an exception that it
does not catch. Because the program does not specify a throws clause to declare this fact, the
program will not compile.
// This program contains an error and will not compile.
class ThrowsDemo {
static void throwOne() {
System.out.println("Inside throwOne.");
throw new IllegalAccessException("demo");
}
public static void main(String args[]) {
throwOne();
}
}
To make this example compile, you need to make two changes. First, you need to declare
that throwOne( ) throws IllegalAccessException. Second, main( ) must define a try/catch
statement that catches this exception.
The corrected example is shown here:
// This is now correct.
class ThrowsDemo {
static void throwOne() throws IllegalAccessException {
System.out.println("Inside throwOne.");
throw new IllegalAccessException("demo");
}
public static void main(String args[]) {
try {
throwOne();
} catch (IllegalAccessException e) {
System.out.println("Caught " + e);
}
}
}
Here is the output generated by running this example program:
inside throwOne
caught java.lang.IllegalAccessException: demo
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